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Brut [27]
3 years ago
7

Need help ASAP on quiz! pictures provided

Mathematics
1 answer:
vazorg [7]3 years ago
8 0

Answer:

I got the answer but i need my notes! ill come back real quick

Step-by-step explanation:

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Working alone, Jack can do a puzzle in 5 hours. With his brother's help, the two can do the same puzzle in 2 hours. How long wou
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3 hours

Step-by-step explanation:

5 - 2 = 3

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Im pretty sure it is 48 but it could be 96

Step-by-step explanation:

I just found the area and halved that.

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Find the slope of the line.
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Slope is -3

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rise over run

The rise is negative so it turns into a negative #

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8 0
4 years ago
what are the x-coordinates for the maximum points in the function f(x) = 4 cos(2x- pi) from x = 0 to x= 2 pi?
julsineya [31]

Answer:

\frac{\pi }{2} and \frac{3\pi }{2}

Step-by-step explanation:

To find the max points we need to take the derivative of the function and then find the critical values.

First we take the derivative:

f(x) = 4cos(2x-\pi )\\f'(x)=-4sin(2x-\pi )(2)\\f'(x)=-8sin(2x-\pi )\\

Now we need to find when f'(x)=0 to find the critical values.

0=-8sin(2x-\pi )\\0=sin(2x-\pi )\\sin^{-1}0=2x-\pi \\0=2x-\pi \\\pi =2x\\\frac{\pi }{2} =x

The critical values will be

\frac{\pi }{2} n for any integer n

between 0 and 2 pi, the critical values will be

0, \frac{\pi }{2} ,\pi ,\frac{3\pi }{2},2\pi

We can determine if these are minimums or maximums by using the second derivative test.

So we need to take the second derivative;

f'(x)=-8sin(2x-\pi )\\f''(x) = -8cos(2x-\pi )(2)\\f''(x)=-16cos(2x-\pi)

We need to see if the second derivative is positive or negative to determine if it is a max or min.

f''(0) = 16\\f''(\frac{\pi}{2})=-16\\f''(\pi )=16\\f''(\frac{2\pi}{3}) = -16\\

Since the second derivative is negative at

\frac{\pi }{2} and \frac{3\pi }{2}

we know both of those are the x-values of maximums.

5 0
4 years ago
-3z - z equivalent expression
evablogger [386]
-4z is equivalent. You’re moving further down the number line in the negative direction.
8 0
3 years ago
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