The letter E would represent 9.
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Answer:
Yes, the sum of any two lengths is greater than the third length
Step-by-step explanation:
Answer:
The correct answer is the linear model would be y = 500x - 390 where x is the number of swords sold in a month and y is the net monthly profit; B. 4.96 ≈ 5 swords monthly.
Step-by-step explanation:
Let x number of swords are sold per month.
Cost price of the swords per month is $ 195x.
Fixed cost to maintain the website per month is $390.
Total cost incurred per month is $ (195x + 390).
Selling price per katana is $695.
Total selling price of x swords per month is $695x.
Therefore, Net monthly profit y =695x - (195x + 390)
⇒ y = 695x - 195x - 390
⇒ y = 500x - 390
Thus the linear model would look like y = 500x - 390 where x is the number of swords sold in a month and y is the net monthly profit.
B. Now, given monthly profit y = $2090.
Thus the number of swords needed to be sold is
2090 = 500x - 390
⇒ 2480 = 500x
⇒ x = 4.96
A minimum of 5 swords need to be sold to get a monthly profit of more than $2090.
Answer:723.202
Step-by-step explanation:
We have five value in the data-set
The third value will be 10 since we want the median to be 10
We want the mean to be 14
To find the mean of a data set, we divide the sum of the values by the number of values
Mean = Sum of values ÷ Number of values
14 = Sum of values ÷ 5
Sum of values = 14 × 5
Sum of values = 70
So we need 5 values that add up to 70, one of the value is 10, which is the median. We would want two values that are smaller than 10 and two values more than 10.
These four value must add up to 70 - 10 = 60
From here we can do trial and error:
Choose any two values less than 10, say 9 and 8
We now have in total 8 + 9 + 10 = 27
We have 70 - 27 = 43 left to find
Choose any two values that are bigger than 10 that add up to 43, for example, 20 and 23
Now we have our 5 values;
8 9 10 20 23
Do the checking bit:
We can see from the set, the median is 10
Mean = [8+9+10+20+23] ÷ 5 = 70 ÷ 5 = 14
We can have values other than 8, 9, 20 and 23 as long as two values smaller than 10 and two values more than 10. All five values must add up to 70.