Nevermind did not mean to answer going t type
Answer:
Trying to help out, I think it's appropriate
Step-by-step explanation:
Answer:
x=6
Step-by-step explanation:
5x+9-3x=21
5x-3x=21-9
2x=12
x=6
Answer:
Today: Monday, 12 October 2020
Hour: 23.39 WIB (in Indonesia)
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-5x - - 4x - 10
-5x + 4x - 10
-x - 10
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1