The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
-x and +6x, also known as 6x - x = 5x
Lastly, you just add in the -2 and get:
X^3 + 5x^2 + 5x - 2
The simple interest formula is A = P(1 + rt) in which A is the total of money after interest, P is your principal (starting) amount, r is the interest rate, and t is the amount of time.
For 1), plug in your variables to get A = 1500(1 + (7/100*1.5)). Simplify, and you'll get A = 1500*1.105, and finally your answer, $1,657.50.
<span>For 2), add your interest and principal amount, then plug in your variables to get 676 = 520(1 + 5r). Distribute to get 676 = 520 + 2600r. Subtract 520 from 676 to get 156 = 2600r, then divide both sides by 2600 to get a rate of 0.06, or 6%.
For 3), add your interest and principal amount, then plug in your variables to get 1599 = 1300(1 + 5.75t). Distribute to get 1599 = 1300 + 7475t. Subtract 1300 from both sides to get 299 = 7475t, and then divide both sides by 7475 to get .04 = t, or a time period of four years.
The other two problems can be solved using the formula and steps described above. If you still need help with them, leave a comment and I will solve those as well. </span>
15 can be 15/1 = 30/2
30/2 + 9/2 = 39/2
Answer:
Step-by-step explanation:
90-2(a-3)^2
=88{(a)^2-2*a*3+(3)^2]
=88[a^2-6a+9}
=88a^2-528a+792
