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Sonja [21]
3 years ago
13

Can someone please help, I'll give brainliest!!! WORTH 40 PTS!

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0

Answer:

X = 14.48528137

Step-by-step explanation:

  1. ADD 72 TO BOTH SIDES
  2. SQUARE ROOT 72
  3. ADD 6
  4. X = 14.48528137
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PLEASE HURRY OMG
Nonamiya [84]

Answer:

Step 3

Step-by-step explanation:

The 28 just disappeared -->

Step 2

3 x + 28 = 15

Step 3

3 x = 15

8 0
3 years ago
Read 2 more answers
Tyler is offered to choose between three boxes that look identical. The first box contains 1 red pills and 19 blue pills, the se
Dafna1 [17]

Answer:

A) 0.15

B) 0.36

Step-by-step explanation:

First Box consist 1 red pills and 19 blue pills

second box consist 6 red pills and 14 blue pills

Third box consist 2 red pills and 18 blue pills

a) Prob ( randomly chosen pill is red) = \frac{1}{3} \times \frac{1}{20} + \frac{1}{3} \times \frac{6}{20} + \frac{1}{3} \times \frac{2}{20}

\frac{1}{60} (1+6+2) = 0.15

b)Prob ( 1 reds and 10 blue pilss) =\frac{1}{3} \frac{^1C_1\times ^{19}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^6C_1\times ^{14}C_{10}}{^{20}C_{11}} + \frac{1}{3} \frac{^2C_1\times ^{18}C_{10}}{^{20}C_{11}}

= \frac{1}{3} 1.106 = 0.368

7 0
3 years ago
A student entering a doctoral program in educational psychology is required to select courses from the list of courses provided
SVEN [57.7K]

A) The possible three-course selections are as shown below.

B) The likelihood of selecting the combinations is 0.1 since there are 10 combinations in total.

<h3>How to solve probability combinations?</h3>

A combination operator can be used when we need to find the number of ways to select "k" items from a set of "n" items. It is also called a 'choose' operator where it is read as 'n choose k' and is represented and calculated as given below

From the choices given, there are 5 courses which are given below:

EPR 605

EPR 643

EPR 648

EPR 674

EPR 681

We need to find the combinations of 3 of these given 5 courses, which are given below (omitting the course code, EPR):

605-643-648

605-643-674

605-643-681

605-648-674

605-648-681

605-674-681

643-648-674

643-648-681

643-674-681

648-674-681

10 of the given choices of combinations are possible since they do not include a repeated course number.

The likelihood of selecting the combination of EPR 681, EPR 648, and EPR 605 is 0.1 since there are 10 combinations in total.

Complete question is;

A student entering a doctoral program in educational psychology is required to select three courses from the list of courses provided as part of his or her program. List all possible three-course selections. Comment on the likelihood that EPR 681, EPR 648, and EPR 605 will be selected. Select all the possible three-course selections below.

A. 648, 674, 605

B. 681, 648, 605

C. 681, 674, 605

D. 681, 681, 648

E. 674, 643, 674

F. 674, 605, 643

G. 681, 648, 674

H. 681, 681

I. 681, 648, 643

J. 648, 605, 643

K. 648, 674, 643

L. 681, 605, 643

M. 643, 694, 643

N. 681, 674, 643

Read more about Probability Combinations at; brainly.com/question/3901018

#SPJ1

8 0
2 years ago
Angle C is inscribed in circle O.
Nitella [24]

Answer:

5units

Step-by-step explanation:

The triangle inscribed in the circle is a right angled triangle with angle C being 90°.

The diameter of the circle AB is the hypotenuse of the triangle.

Before we can get the radius, we need to get the diameter AB using Pythagoras theorem.

|AB|² = |AC|²+|BC|²

|AB|² = 6²+8²

|AB|² = 36+64

|AB|² = 100

|AB| = √100

|AB| = 10

Diameter of the circle = 10units

Radius = diameter/2 = |AB|/2

Radius = 10/2

Radius = 5units

8 0
4 years ago
In a test for extrasensory perception, the experimenter looks at cards containing either a star, circle, wave, or square. (The s
Gwar [14]

Answer:

0.0139

Step-by-step explanation:

Given that in a test for extrasensory perception, the experimenter looks at cards containing either a star, circle, wave, or square. (The subject cannot see the cards.)

Probability for guessing a correct shape out of 4 shapes = 0.25

Each trial is independent of the other

Hence X no of correct guesses is binomial with n = number of cards = 20 and p = constant probability =0.25

the probability a subject correctly guesses at least 10 of the 20 shapes

=P(X\geq 10)\\= 1-F(9), where F represents the cumulative probability upto 9

= 0.0139

3 0
3 years ago
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