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SashulF [63]
3 years ago
12

I posted 2 question of this but nobody answered first answer gets brainliest and a thanks and 5 stars and 20 points and do all o

f them or half no links ASAP guessers will be reported

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

14. 13.65

15. 7.53

17. 0.0371

18. 0.81

19. 0.864

Here are some answers! Hope this helps

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Is Anyone know the answer????
Alinara [238K]

Answer:

Angle 1 = 40

Step-by-step explanation:

Angle 1 and Angle 2 are alternate angles. So,

2x + 20 = 3x + 10

3x - 2x = 20 - 10

x = 10

Angle 1 = 2x + 20 = 2 x 10 + 20 = 40

4 0
2 years ago
Read 2 more answers
What is the value of the expression below if y=5
Neko [114]

Answer:

25

Step-by-step explanation:

8*5=40

40+6=46

46-10=36

36-9=25

5 0
3 years ago
Use a graphing calculator to graph the function and its parent function. Then describe the transformations, f(x)=(x+3)+1/4​
nlexa [21]

Most of the graphing resources used shows that the graph is translated up by 3.25 (3 + 1/4). If you add the 3 and the 1/4, you get the equation of a line:

f(x) = x + 3.25,

which means that the graph of f(x)= x now has a y intercept of 3.25.

The graphs are below. The red line represents f(x) = x, and the green line represents (x+3)+1/4. Hope this helps!

8 0
3 years ago
What is the coefficient of the term of degree 4 in this polynomial?<br> x^8+2x^4 - 4x^3 + x^2-1
never [62]

Answer:

2

Step-by-step explanation:

the coefficient is the number that multiply the letter

5 0
3 years ago
10 points!!! please help :(
daser333 [38]
To complete the identity, we need these fundamental identities:

1)\displaystyle{sec(x)=\frac{1}{cos(x)}

2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)

\displaystyle{csc(x)= \frac{1}{sin(x)}


Thus, by identity 1 we have:

\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}

by identity :

\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)

recall the values :

\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\

\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0, 


so: 

cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)


Putting all these together, we have:


\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}

which is equal to csc(\theta), by identity 3


Answer: D
7 0
3 years ago
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