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SashulF [63]
3 years ago
12

I posted 2 question of this but nobody answered first answer gets brainliest and a thanks and 5 stars and 20 points and do all o

f them or half no links ASAP guessers will be reported

Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
6 0

Answer:

14. 13.65

15. 7.53

17. 0.0371

18. 0.81

19. 0.864

Here are some answers! Hope this helps

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Negative. A negative number times a positive number is equal to a negative number. X multiplied by Y is a positive.
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228 + 6 =<br> R<br> What is the quotient
cricket20 [7]

228 + 6 = 224 + 6 + 4 = 230 + 4

= 234

Answer: 234

ok done. Thank to me :>

4 0
2 years ago
How do you find the quotient of -4.8 divided by 0.6
Dafna11 [192]

Answer:

Step-by-step explanation:

− 4.8 /0.6 =−8

3 0
3 years ago
Find the missing side lengths. leave your answers as radicals in simplest form.
Murrr4er [49]

Answer:

x = 4 , y = 2

Step-by-step explanation:

Using the sine / tangent ratios in the right triangle and the exact values

sin60° = \frac{\sqrt{3} }{2} and tan60° = \sqrt{3} , then

sin60° = \frac{opposite}{hypotenuse} = \frac{2\sqrt{3} }{x} = \frac{\sqrt{3} }{2} ( cross- multiply )

x \sqrt{3} = 4\sqrt{3} ( divide both sides by \sqrt{3} )

x = 4

and

tan60° = \frac{opposite}{adjacent} = \frac{2\sqrt{3} }{y} = \sqrt{3} ( multiply both sides by y )

y \sqrt{3} = 2\sqrt{3} ( divide both sides by \sqrt{3} )

y = 2

6 0
3 years ago
You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,
Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
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