You have 2 options.
I will show you the most efficient one, but later I will tell you the other.
-4x+6y=12
6y=4x+12
y=4/6x+12
y=2/3x+12
This tells us the point (0,12) as 12 is where it meets the y-axis (that is why you add it)
And then using the slope, 2/3 we can get (2,15) (which is up 3, right 2)
Just graph those, I would show you exactly, but I cannot add attachments sadly.
The other way (which I won’t show it all as the results would end out with the same line) is to fill in x, then y, with 0
So -4*0+6y=12 which means x=0 and you are solving for y and -4x+6*0=12 which means y=0 and you are solving for x
Answer:
27:9 3:1.................
Answer:
Vertical and supplementary
5/8 or .625 is the answer
You are correct in thinking that the columns of the first matrix must match with the rows of the second matrix.
So for example, we can multiply a 1 x 5 matrix with a 5 x 7 matrix. The two matching '5's are directly what make multiplication possible in this case. For your problem, the first two '3's match and multiplication is possible.
The rows of the first matrix don't need to match with the columns of the second matrix.
