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Sidana [21]
3 years ago
12

Please hurry and answer this *late work*

Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer:

x = -25, 39

Step-by-step explanation:

7 + 32 = 39

7 - 32 = -25

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100 POINTS PLUS BRAINLY
Iteru [2.4K]

Answer:

\sf adjacent  = 4.5 \ ft

Given:

  • opposite side: 13 ft
  • adjacent unknown
  • angle of 71°

using tan rule:

\sf tan(x) = \dfrac{opposite}{adjacent}

\hookrightarrow \sf tan(71) = \dfrac{13}{adjacent}

\hookrightarrow  \sf adjacent  = \dfrac{13}{tan(71) }

\hookrightarrow  \sf adjacent  = 4.5

4 0
2 years ago
Read 2 more answers
Write the equation of the line that passes through 7, 0 and is parallel to y = -3x + 4​
Mazyrski [523]

Answer:

y = - 3x + 21

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - 3x + 4 ← is in slope- intercept form

with slope m = - 3

Parallel lines have equal slopes , then

y = - 3x + c ← is the partial equation

To find c substitute (7, 0 ) into the partial equation

0 = - 21 + c ⇒ c = 0 + 21 = 21

y = - 3x + 21 ← equation of parallel line

8 0
3 years ago
37.392÷0.09 to the nearest hundredth
rosijanka [135]

Answer:

415.47

Step-by-step explanation:

5 0
3 years ago
If MP is a perpendicular bisector to LN, find each value (picture attached)
solong [7]

Answer:

x=4, MN= 37, LM= 37, y=7.

Step-by-step explanation:

If MP is a perpendicular bisector to LN, then NP and LP are equivalent.

(Solve for y)

2y+2= 16

(Move the +2 to the right side of the equation)

2y= 14

(Divide both sides by 2 to isolate the variable)

y=7

To find x and the measure of MN and LM, solve for x in the following equation:

7x+9 = 11x-7

(Move 7x to the right side of the equation)

9 = 4x-7

(Move -7 to the right side of the equation.)

16= 4x

(Divide both sides by 4 to isolate the variable.)

4= x

Plug x back into both equations to get the measure of MN and ML

MN=7(4)+9

MN= 28+9

MN= 37

LM= 11(4)-7

LM= 44-7

LM= 37

I hope this helps!

3 0
3 years ago
Read 2 more answers
Assigned newbits with the opposite values of oldbits if flipbits is true. ex: if oldbits = [1, 1, 0, 1] and flipbits is 1, then
Kisachek [45]

Franck's answer is better (using ~), but I just wanted to point out that the conditional in yours is slightly redundant. It's easy to forget that, since you already have a boolean value, you don't need to perform a comparison in your conditional. So you could have just done this...

<span>if x x = false; else x = true; <span>end</span></span>
5 0
3 years ago
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