Answer:
Infinite pairs of numbers
1 and -1
8 and -8
Step-by-step explanation:
Let x³ and y³ be any two real numbers. If the sum of their cube roots is zero, then the following must be true:
![\sqrt[3]{x^3}+ \sqrt[3]{y^3}=0\\ \sqrt[3]{x^3}=- \sqrt[3]{y^3}\\x=-y](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E3%7D%2B%20%5Csqrt%5B3%5D%7By%5E3%7D%3D0%5C%5C%20%5Csqrt%5B3%5D%7Bx%5E3%7D%3D-%20%5Csqrt%5B3%5D%7By%5E3%7D%5C%5Cx%3D-y)
Therefore, any pair of numbers with same absolute value but different signs fit the description, which means that there are infinite pairs of possible numbers.
Examples: 1 and -1; 8 and -8; 27 and -27.
For this case we have the following fractions:

We must rewrite the fractions, using the same denominator.
We have then:
We multiply the first fraction by 11 in the numerator and denominator:

We multiply the second fraction by 2 in the numerator and denominator:

Rewriting we have:
For the first fraction:

For the second fraction:

We note that:

Answer:
The fractions are not equivalent:

Answer:
2:3
Step-by-step explanation:
The common factor between 10 and 15 is 5.
5 goes into 10 twice and 15 three times.
÷ 
Solution:
2(6+7)= 3(5+2)
Step ; 1 { Solving first Term i.e LHS }
LHS : 2 ( 6 + 7)
☞ 2 ( 13)
☞ 2 × 13
☞ 26
Now, RHS ; 3 ( 5 + 2)
☞ 3 ( 7)
☞ 21
From Equation 1 and 2, We can LHS and RHS are not Equal.
Therefore, 26≠ 21.
13
14=2•7
15=3•5
16=2•2•2•2
17
18=2•3•3
19
20=2•2•5
...