You are buying gifts for 10 people. you decide to buy each person a CD or a DVD.
2 answers:
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Answer:
You need a z-score of at least 1.09 to get accepted.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
To get accepted into OSU, you need at least a 27. What is the z-score you need to get accepted?
We need to find Z when X = 27. So
You need a z-score of at least 1.09 to get accepted.
Given that <span>the area of the playground is 910 square feet, let the length of the playground be x, then the width of the playground is given by 
</span>Given that <span>the fence along three of the sides costs $5 per foot and </span>the fence along the fourth side, which will be made of brick, costs $15 per foot. <span>Let the side with the brick fence be the side which measures x feet.
</span>
Then the cost for fencing the entire playground is given by
For, minimum cost,
But x can't be negative.
Therefore, <span>the length of the brick fence that will minimize the cost of enclosing the playground is 21.33 feet.</span>
</span>Given that <span>the fence along three of the sides costs $5 per foot and </span>the fence along the fourth side, which will be made of brick, costs $15 per foot. <span>Let the side with the brick fence be the side which measures x feet.
</span>
Then the cost for fencing the entire playground is given by
For, minimum cost,
But x can't be negative.
Therefore, <span>the length of the brick fence that will minimize the cost of enclosing the playground is 21.33 feet.</span>