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Elis [28]
2 years ago
5

50 POINTS PLEASE HELP ASAP THE FULL QUESTION IS ON THE PICTURE

Mathematics
1 answer:
Deffense [45]2 years ago
5 0
The first one is 50 cm
second is 153 ft
third one is 132 m
sorry if it’s wrong
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A data set has a mean of x = 71 and a standard deviation of 11.6. Find the z-score for each of the following.
olchik [2.2K]

Answer:

WHY MUST I CRYYYYY

Step-by-step explanation:

5 0
2 years ago
20 Points + Brainliest for the answer and Explanation!!!
Vlad1618 [11]

Answer:

P+Q=5x^2+4

Q-P=-x^2-4x+16

Step-by-step explanation:

We are given

P=3x^2+2x-6

Q=2x^2-2x+10

Calculation of P+Q:

P+Q=3x^2+2x-6+2x^2-2x+10

now, we can combine like terms

P+Q=3x^2+2x^2+2x-2x+10-6

P+Q=5x^2+0+4

P+Q=5x^2+4

Calculation of Q-P:

Q-P=2x^2-2x+10-(3x^2+2x-6)

Firstly, we will distribute negative sign

Q-P=2x^2-2x+10-3x^2-2x+6

now, we can combine like terms

Q-P=2x^2-3x^2-2x-2x+6+10

Q-P=-x^2-4x+16

8 0
2 years ago
Which of the following points is in the solution set of y>x2+7x-14​
Lesechka [4]

Answer:

Observation : No two such factors can be found !! Conclusion : Trinomial can not be factored. Equation at the end of step 1 : x2 - 7x - 14 = 0. Step 2 : Parabola, Finding the Vertex: 2.1 Find the Vertex of y = x2-7x-14

7 0
2 years ago
Suppose f(7) = 5​, f'(7) = 8​, g(7) = 3​, and g'(7) = 4. Find h(7) and h'(7)​, where h(x ) = 4f (x) + 3g(x).
dusya [7]

Answer:

h(7) = 29

h'(7) = 44

Step-by-step explanation:

If h(x) =4f(x)+3g(x), to find h(7) we can substitute the values of f(7) and g(7) and we get:

h(7)=4f(7)+3g(7)\\h(7)=4(5)+3(3)\\h(7)=20+9\\h(7)=29

To find the derivative, we know that the derivative of a sum of functions equals the sum of the derivatives of those functions.

This would mean that h'(x)=4f'(x)+3g'(x), we can substitute the values for f'(7) and g'(7)

h'(7)=4f'(7)+3g'(7)\\h'(7)=4(8)+3(4)\\h'(7)=32+12\\h'(7)=44

7 0
3 years ago
At the start of 2014 Mikes car was worth £12000. the value of his car decreased 30% every year.
Readme [11.4K]
Answer:

The worth of car at the start of 2014 = $12000

The value of the car decreased 30% every year.

At start of 2015:

30% of 12000 = \frac{30}{100} \times 12000

100

30

×12000 = 3600

So, the value of the car at start of 2015 = 12000-3600 = $8400.

At start of 2016:

30% of 8400 = \frac{30}{100} \times

8400

100

30

×8400 = 2520

So, the value of the car at start of 2016 = 8400-2520 = $5880.

At start of 2017:

30% of 5880 = \frac{30}{100} \times

5880
100

30

×5880 = 1764

the value of the car at start of 2017 = 5880-1764 = $4116.

So, the value of his car at the start of 2017 is $4116.
6 0
2 years ago
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