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Solnce55 [7]
3 years ago
14

Find the length of side x in simplest radical form with a rational denominator.

Mathematics
1 answer:
NeTakaya3 years ago
5 0

Answer:

x = 2 \sqrt{5}

Step-by-step explanation:

\sin \: 30 \degree =  \frac{ \sqrt{5} }{x}  \\  \\  \frac{1}{2} =  \frac{ \sqrt{5} }{x}  \\  \\x = 2 \sqrt{5}

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15 points please answer
Paraphin [41]

Answer:

x^5*sqrt(x)

Step-by-step explanation:

5*6 = 30 with one left over

7 0
2 years ago
Please help <br> A: 8<br> B: 22<br> C: 32<br> D: 44
horrorfan [7]

Answer:32, XZ is twice the size of AC

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Mr. See weights his grades. Tests are worth 60%, quizzes are worth 25% and homework is 15%. Joey's test average is an 82, his qu
goldenfox [79]

Answer:

83.15

Step-by-step explanation:

Joey's current grade can be determined by weighting his scores with the weights given and adding the results

Tests = 0.6 x 82 = 49.2

Quizzes = 0.25 x 77 = 19.25

homework = 0.15 x 98 = 14.7

49.2 + 19.25 + 14.7 = 83.15

4 0
3 years ago
HELP ME!!!!! Which choices are equivalent to the fraction below? CHECK ALL THAT APPLY.
slavikrds [6]

Answer:

A and E

Step-by-step explanation:

9^3 / 9^3

Same number on top and bottom so 1 is an answer

look at the exponents, when dividing with exponents, you just subtract them, so it could also be 9^0, which is also 1

3 0
3 years ago
Read 2 more answers
A sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to
Archy [21]

Answer:

0.2916, 0.1488, 0.0319

Step-by-step explanation:

Given that a sign on the pumps at a gas station encourages customers to have their oil checked, and claims that one out of 10 cars needs to have oil added.

Since each trial is independent there is a constant probability for any random car to need oil is 0.10

Let X be the number of cars that need oil

A) Here X is BIN(4,0.1)

P(X=1) = 4C1(0.1)(0.9)^3 \\= 0.2916

B) Here X is Bin (8, 0.1)

P(x=2) = 8C2 (0.1)^2 (0.9)^6\\\\=0.1488

C) Here X is Bin (20,5)

P(x=5) = 20C5 (0.1)^5 (0.9)^{15} \\=0.0319

3 0
3 years ago
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