Answer:
d(A,B)=1
Step-by-step explanation:
To find distance between points A(xA,yA) and B(xB,yB), we use formula:
d(A,B)=(xB−xA)2+(yB−yA)2−−−−−−−−−−−−−−−−−−−√
In this example: xA=3 , yA=5 , xB=3 and yB=6 so:
d(A,B)d(A,B)d(A,B)=(3−3)2+(6−5)2−−−−−−−−−−−−−−−√=0+1−−−−√=1
Answer: 
<u>Step-by-step explanation:</u>
f(x) = A sin (Bx - C) + D
- amplitude = |A|
- period =

- phase shift =
- vertical shift = D
<u>A</u>
amplitude of 3 is given so 3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3
<u>B</u>
period of 6π is given so 
<u>C</u>

<u>D</u>
vertical shift of -1 is given so -1 = D
Now, substitute the values of A, B, C, and D into the formula (above):

Next, solve when x = 2π






