A sine function had an amplitude of 3, period of 6pi, horizontal shift of 3pi/2, & vertical shift of -1.
1 answer:
Answer:
<u>Step-by-step explanation:</u>
f(x) = A sin (Bx - C) + D
amplitude = |A| period = phase shift = vertical shift = D <u>A</u>
amplitude of 3 is given so 3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3
<u>B</u>
period of 6π is given so
<u>C</u>
<u>D</u>
vertical shift of -1 is given so -1 = D
Now, substitute the values of A, B, C, and D into the formula (above):
Next, solve when x = 2π
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