4.42 g mass of CCl4 is required to prepare a 0.25 m solution using 115 g of hexane.
It's easy to find the molecular mass of a compound with these steps: Determine the molecular formula of the molecule. Use the periodic table to determine the atomic mass of each element in the molecule. Multiply each element's atomic mass by the number of atoms of that element in the molecule.
The molar mass of any compound can be found out by adding the relative atomic masses of each element present in that particular compound.
Hexane is an organic compound, a straight-chain alkane with six carbon atoms and has the molecular formula C₆H₁₄.
Therefore,
⇒ 0.115 g of Hexane x (0.25 mol CCl4/1 mol hexane) x (153.81 g of CCl4/1 mol CCl4) = 4.42g CCl4.
To learn more about CCL4 and Hexane here
brainly.com/question/15156642
#SPJ4
Answer:
That substance is an element.
Explanation:
Atoms in a substance have the same identity, that substance is an element. in other words if all atoms are alike then it is an element.
Ive gotten this question asked to me before.
Answer:
Glycerol;Pyruvate
Explanation:
Metabolism of triglycerides occur through a process known as lipolysis. During triglyceride metabolism, <u>Glycerol </u><u>is converted to pyruvate or glucose through glycolysis or gluconeogenesis respectively</u>. Glycerol enters these pathways by being converted to glycerol-3-phosphate (reaction catalyzed by glycerol kinase) which can in turn be converted to dihydroxyacetone phosphate (reaction catalyzed by glycerol-3-phosphate dehydrogenase).
NOTE: Dihydroxyacetone phosphate is a compound/substrate found in both glycolysis and gluconeogenesis.
The end product of glycolysis is pyruvate; this <u>pyruvate, under aerobic condition is converted to acetyl coA</u> (reaction catalyzed by pyruvate dehydrogenase complex), an intermediary of the Tricarboxylic acid cycle.
Answer:
if i remember correctly i beleive its A 1.8 x 10^24
but im not for sure also i think you forgot the 24
Explanation:
Answer: B, the gas is being squeezed out of the liquid.
Explanation: The gas does not want to be trapped inside of the liquid, so it is trying to force it’s way out. Therefore creating more pressure in the container or whatever the liquid is being held in.
