To investigate the relationship between enzyme activity and substrate concentration, a student is supposed to prepare a reaction
solution containing 0.25% substrate. instead, the student prepares a reaction solution containing 0.025% substrate. what effect would this error have on the outcome of the experiment? [2 pt; l2; i.a.5]
As i know for finding the speed of an enzyme to do it's work this formula is used v=v max *[s]/k m +[s] km shows the amount of substrate we need to make the enzyme work with half of it's max speed and [s] shows the <span>substrate. we can say that 0.025/0.25=0.1 so the speed is about 0.1 of we wanted to </span> investigate at the beginning (we don't consider [s] in the <span>Denominator to solve it easier) </span>
The replacing of sodium hydroxide with potassium hydroxide
(KOH) to the reaction will least affect the organic product that forms.
Potassium hydroxide is an
inorganic compound with the formula KOH, and is commonly called caustic potash. Along with sodium hydroxide, this colorless
solid is a prototypical strong base.
Solid is stayed undissolved since the arrangement is gotten super saturated. On the off chance that solid molecule is available recrysallization won't happen in this way we need expel the solid molecule by filtarion in hot condition itself . Subsequently, arrangement become totally homogenous and recrysallization item will shaped by moderate cooling
