Question

To investigate the relationship between enzyme activity and substrate concentration, a student is supposed to prepare a reaction solution containing 0.25% substrate. instead, the student prepares a reaction solution containing 0.025% substrate. what effect would this error have on the outcome of the experiment? [2 pt; l2; i.a.5]

Answer 1

As i know for finding the speed of an enzyme to do it's work this formula is used
v=v max *[s]/k m +[s]
km shows the amount of substrate we need to make the enzyme work with half of it's max speed and [s] shows the substrate.
we can say that 0.025/0.25=0.1 so the speed is about 0.1 of we wanted to
investigate at the beginning  (we don't consider [s] in the Denominator to solve it easier)