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2 years ago

Please help!!! Don’t mind the one I picked, I accidentally clicked one.

Mathematics

1 answer:

natima [27]2 years ago

8 0

Answer:

y<2/3x-1

Step-by-step explanation:

plotted point is on -1

slope of the line is rise 2, run 3

so its the last option

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There is 28 kg 750 g of sugar in a sack. How many tins of 500 g sugar can be filled using the sugar in the sack?

vovangra [49]

Answer:

Step-by-step explanation:

28 kg + 750 g = 28*1000 + 750

28000 + 750

= 28750 g

Number of sack = Total quantity of sugar ÷ quantity of sugar in a sack

= 28750 ÷ 500

= 57 sacks

6 0

2 years ago

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Solve the equation x2-16x+54=0

kari74 [83]

Answer:

x1 = 8+√10, x2 = 8 -√10

Step-by-step explanation:

x² - 16x + 54 = 0

$x = \frac{-b +/-\sqrt{b^{2} -4ac} }{2a} \\x = \frac{-(-16)+/-\sqrt{(-16)^{2} -4*1*54} }{2*1} \\\\\\x = \frac{16+/-\sqrt{(40)} }{2*1} = 8+/-\sqrt{10} \\\\x_{1} = 8+\sqrt{10}\\\\x_{2} =8-\sqrt{10}$

7 0

2 years ago

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Part C What conclusion can you draw from this? To determine whether they used the same number of tiles, set the two expressions

LUCKY_DIMON [66]

Answer:

We can conclude that someone used more tiles then the other because both equations are not equal.

Step-by-step explanation:

If you try to solve it both equations will not be shown as equal.

4 0

2 years ago

Factoring polynomials

-Dominant- [34]

1. x(2x^2-x+4)
2.-3(y-1)(y+2)
3.-(11w^2+18w-1)

7 0

3 years ago

How many Solutions does this system have? (1 point)

mixas84 [53]

The given system of equation that is $2x+y=3$ and $6x=9-3y$ has infinite number of solutions.

Option -C.

<u>Solution:</u>

Need to determine number of solution given system of equation has.

$\begin{array}{l}{2 x+y=3} \\\\ {6 x=9-3 y}\end{array}$

Let us first bring the equation in standard form for comparison

$\begin{array}{l}{2 x+y-3=0} \\\\ {6 x+3 y-9=0}\end{array}$

$\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}} \neq \frac{c_{1}}{c_{2}}$

To check how many solutions are there for system of equations $a_{1} x+b_{1} y+c_{1}=0 \text{ and }a_{2} x+b_{2} y+c_{2}=0$ , we need to compare ratios of $\frac{a_{1}}{a_{2}}, \frac{b_{1}}{b_{2}} \text { and } \frac{c_{1}}{c_{2}}$

In our case,

$a_{1} = 2, b_{1}= 1\text{ and }c_{1}= -3$

$a_{2} = 6, b_{2} = 3,\text{ and }c_{2} = -9$

$\begin{array}{l}{\Rightarrow \frac{a_{1}}{a_{2}}=\frac{2}{6}=\frac{1}{3}} \\\\ {\Rightarrow \frac{b_{1}}{b_{2}}=\frac{1}{3}} \\\\ {\Rightarrow \frac{c_{1}}{c_{2}}=\frac{-3}{-9}=\frac{1}{3}} \\\\ {\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}=\frac{1}{3}}\end{array}$

As $\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}$ , so given system of equations have infinite number of solutions.

Hence, we can conclude that system has infinite number of solutions.

5 0

2 years ago