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Margarita [4]
2 years ago
6

Which situation would most likely take place in a market economy?

Mathematics
2 answers:
Yuliya22 [10]2 years ago
7 0

Answer:

Two car companies compete to make the cheapest electric car.

Step-by-step explanation:

BlackZzzverrR [31]2 years ago
3 0
B is the answer thank me
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Jose has 4 friends and 3 apples how much would each friend get if he shared
blsea [12.9K]

\bf \cfrac{\stackrel{\textit{total amount of apples}}{3}}{\stackrel{\textit{total amount of people}}{4}}\qquad \qquad \quad\stackrel{Jose}{ \cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}+\stackrel{friend}{\cfrac{3}{4}}=\cfrac{12}{4}=3

5 0
3 years ago
Read 2 more answers
What is the solution set of {x | x < 2} {x | x ≥ 2}? all numbers less than -5 and greater than 5 the empty set the numbers be
juin [17]

Answer:

The solution set is the empty set.

Step-by-step explanation:

{x | x < 2} is the set of all numbers less than 2. This means x can take values such as 1.99, 0, -2000 and so on. That is, all values less than 2.

{x | x ≥ 2} is the set of all numbers equal to or greater than 2. This means x can take values such as 2, 2.1, 5000, and so on. That is, 2 or any value greater than 2.

Since there is no sign between the two sets, the question is asking for the intersection between these two sets. That is, what elements are common to these two sets? As we can see, the two sets don't have any common element. Hence, their intersection is the empty set.

(Note that the union of these two sets would be the set of all real numbers as that includes all elements from either set).

3 0
2 years ago
What is the slope<br> A. Undefined <br> B. 0
Burka [1]
B. is the correct answer love
6 0
3 years ago
find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on
enyata [817]

Let f(x)=\tan^{-1}x. Then f'(x)=\frac1{1+x^2}. Note that f(0)=0.

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n

This means that for |-x^2|=|x|^2, or -1, we have

\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}

Integrate the series to get

f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

6 0
3 years ago
Yeah i have no clue how to do this and there's two of them soo help is very much appreciated lol
cluponka [151]

Answer:

2^x - 4 is the answer here

5 0
2 years ago
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