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love history [14]
2 years ago
13

What is the solution to this system of equations? -5.9x-3.7y=-2.1 and 5.9x+3.7y=2.1

Mathematics
1 answer:
goblinko [34]2 years ago
3 0

No solution because everything cancels out

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A boy makes a cuboid of plasticine of sides 5cm, 2cm, 5cm. How manny such cuboids will he need to form a cube?
ruslelena [56]

Answer:

Step-by-step explanation:

L.C.M. of 5,2=10

so it should be  of dimensions 10×10×10

it should have 5 cuboids in first row.

then it will make a cuboid 5×10×5

5 cuboids in the second row on top of first row .

Then it will make 5×10×10 cuboid

To make 10×10×10

double the cuboids  to make the length=10 and height=10..

so in all 20 cuboids are needed.

2 rows of 5 cuboids on the floor and 2 rows of 5 cuboids on the top.

in all 10 cuboids of  dimensions 5×2×5

so 9 more cuboids are needed to make a c

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3 years ago
Dion is performing a hypothesis test in which the population mean is 92 and the standard deviation is 2. His sample size is 7 wi
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Answer:

Step-by-step explanation:

7 0
3 years ago
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How do I solve 10p+5=18p-6/2
mihalych1998 [28]
<span>10p+5=18p-6/2 
10p + 5 = 18p -3 
10p - 18 p = -3 -5
-8p = -8
p = -8/-8
p =1</span>
3 0
3 years ago
Solve P=Kt/v for k
yan [13]
Multiple both sides of the equation by V, and divide both sides by T.. You'll get PV/T=KT/V*(V/T)=K.
8 0
3 years ago
What fraction of a year are 31 days ?
Alborosie

9514 1404 393

Answer:

  • non-leap years: 31/365
  • leap years: 31/366

Step-by-step explanation:

As a fraction of the number of days in a calendar year, it will depend on whether the year is a leap year.

non-leap years have 365 days, so 31 days is 31/365 years.

leap years have 366 days, so 31 days is 31/366 years.

_____

If you're asking for the purpose of computing interest, you need to be aware that "ordinary interest" counts 360 days in a year. 31 days would be 31/360 years. "Exact interest" counts 365 days in a year, so 31 days would be 31/365 years.

In astronomy, the definitions of "day" and "year" may vary, depending on the frame of reference and what direction in space marks the boundary of the period. The precise fraction will depend on how you define these terms and where the clock is located.

5 0
2 years ago
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