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photoshop1234 [79]
2 years ago
14

Find an equation in standard form for the hyperbola with vertices at (0,+-6) and asymptote at Y= +- 3/7x

Mathematics
1 answer:
Tasya [4]2 years ago
8 0

Answer:

\frac{y^2}{36}-\frac{x^2}{196}=1

Step-by-step explanation:

From the question we are told that:

Vertices of hyperbola at (0,\pm6)

Asymptotes at Y= \pm 3/7x

Generally the expression for Vertices of hyperbola is mathematically given by

 (0,\pm a)

Therefore

 (0,\pm a)=(0,\pm6)

Comparing variables

 a=6

Generally the expression for Asymptotes of hyperbola is mathematically given by

 y=\pm \frac{a}{b}x

Therefore

 \pm \frac{a}{b}x= \pm \frac{3}{7}x

Therefore

 \frac{6}{b}= \frac{3}{7}

 b=\frac{42}{3}

 b=14

Generally the equation for Hyperbola of hyperbola is mathematically given by

 \frac{y^2}{a^2}-\frac{x^2}{b^2}=1

 \frac{y^2}{6^2}-\frac{x^2}{14^2}=1

 \frac{y^2}{36}-\frac{x^2}{196}=1

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Step-by-step explanation:

Step 1; Whenever you make a payment, make a cash withdrawal, a payment through debit card or an automatic payment the money in your account decreases as you're giving your money to someone else. So the amount of money spent or taken is reduced from the balance in your account.

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Step 2; Total deposits mean all the money that was added into your account. In this month's summary, the individual didn't deposit any money into their account but did get paid twice. They got paid their paycheck twice. The amount paid was $645.30. So total amount deposited was 2 * $645.30= $1290.60.

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