Answer:
I would multiply the first equation by −4 and the second by 3 and add together the two equatins (in columns): ... Step 2. Prepare the equations. Multiply every term in each equation by a ... Subtract Equation (4) from Equation (3). ... How do you solve the system 5x−10y=15 and 3x−2y=3 by multiplication?
Answer:
+ 7 d - 7
7 d2 + d + 1
Step-by-step explanation:
+ 7 d - 7
7 d2 + d + 1
To do this, you cube each section. You cube the 11 and the c^4. 11^3=1331 and (c^4)^3=c^12 (You multiply the 2 exponents). So your answer is 1331c^12
Answer:
A
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Maybe this will spur your memory:
1.)
<u> 1 5 5 2 0 </u>
46 | 71 3 9 2 0
<u> 46</u>
25 3
<u> 23 0 </u>
2 3 9
<u> 2 3 0</u>
9 2
<u> 9 2 </u>
0 0
<u> 0 0</u>
<u />