Answer: Option E) None of the above is true; this enzyme could bind none of these.
Explanation:
Lactose is a dissacharide composed of glucose and galactose. Hence, the enzyme lactase break down lactose into its simple sugar constituents.
However, lactase cannot bind nor break down amino acids, starch (with only glucose units) or sucrose (with two glucose units) because their constituent molecules differ markedly from that of lactose.
Thus, the enzyme lactase could bind with none of the options provided except lactose
When a BB male and a Bb female are crossed, 50% BB and 50% Bb genotypes are produced and a 100% black phenotype.
The entire number of genes that an organism receives from its parents makes up its genotype. Alleles, which are pairs of these genes, are found. One gene is dominant and one gene is recessive in each allele.
The dominant gene is always expressed in a cross if it is present. Only when a pair of alleles is made up of two recessive genes does the recessive gene express itself. In this instance, the white fur is subordinate to the black fur. White fur is represented as b, while black fur is represented as B.
We can see that when we cross the BB male and Bb female, we will get a genotype that is 50% BB and 50% Bb, as well as a phenotype that is 100% black fur.
Parents: BB x Bb
Gametes: B, B, and B, b
Offspring: BB, BB, Bb, Bb
The genotypic ratio = 1:1
The phenotypic ratio = 1:0
Genotype probabilities:
P(BB) = 2/4 = 0.5 or 50%
P(Bb) = 2/4 = 0.5 or 50%
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Answer:
B. Chromosomes
Explanation:
This process is required to produce egg and sperm cells.
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