Dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
As given in the question,
P(x) be the given polynomial
Dividing P(x) by divisor (x-6) we get,
Quotient = Q(x)
Remainder = 5
Relation between polynomial, divisor, quotient and remainder is given by :
P(x) = Q(x)(x-6) + 5 __(1)
Given Q(-6) = 3
Put x =-6 we get,
P(-6) = Q(-6)(-6-6) +5
⇒ P(-6) = 3(-12) +5
⇒ P(-6) =-36 +5
⇒ P(-6) = -31
Now x =6 in (1),
P(6) = Q(6)(6-6) +5
⇒ P(6) = Q(6)(0) +5
⇒ P(6) = 5
Therefore, dividing the given polynomial by (x -6) gives quotient Q(x) and remainder 5 then for Q(-6) = 3 , P(-6) = -31and P(6) =5.
The complete question is:
Dividing the polynomial P(x) by x - 6 yields a quotient Q(x) and a remainder of 5. If Q(-6) = 3, find P(-6) and P(6).
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Answer:
y=3x-5
Step-by-step explanation:
This is the only line that will pass through these points.
It would be c that is the answer
Answer:
50.29 in^2
Step-by-step explanation:
From the circumference we need to find the radius.
Since C = 2*pi*r, r = C / (2*pi).
Here, with C = 25 1/7 in, r = (25 1/7 in) / [ 2(22/7) ], or r = 4 in
The area of the cake is A = pi*r^2, or (here) A = (22/7)(4 in)^2 = 50.29 in^2
Answer:
diameter times height times x = volume
Step-by-step explanation:
using the length times width times height equation for volume.
good luck :)
