Answer:
Step-by-step explanation:1math problem in 30seconds
Answer:There are two right triangles. You need to find the opposite side (the height) of each of them. The difference between the two is the height of the blade, x.
You know the adjacent, 440, and you are looking for the opposite, so you need to use tan for both.
tan (30) = y / 440
y = 440 * tan (30) = 254.034...
tan (38.8) = z / 440
y = 440 * tan (38.8) = 353.769.--
353.8 - 254.0 = 99.8 = 100 feet.
Step-by-step explanation:
Answer:
y=(x+13)/3
Step-by-step explanation:
the question is not quite clear, i think u mean y= -3x + 4
then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3
y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3
Answer: A) 1260
Step-by-step explanation:
We know that the number of combinations of n things taking r at a time is given by :-

Given : Total multiple-choice questions = 9
Total open-ended problems=6
If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,
No. of ways to answer 6 multiple-choice questions
= 
No. of ways to answer 4 open-ended problems
= 
Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems
= 
Hence, the correct answer is option A) 1260
Answer:
A), B) and D) are true
Step-by-step explanation:
A) We can prove it as follows:

B) When you compute the product Ax, the i-th component is the matrix of the i-th column of A with x, denote this by Ai x. Then, we have that
. Now, the colums of A are orthonormal so we have that (Ai x)^2=x_i^2. Then
.
C) Consider
. This set is orthogonal because
, but S is not orthonormal because the norm of (0,2) is 2≠1.
D) Let A be an orthogonal matrix in
. Then the columns of A form an orthonormal set. We have that
. To see this, note than the component
of the product
is the dot product of the i-th row of
and the jth row of
. But the i-th row of
is equal to the i-th column of
. If i≠j, this product is equal to 0 (orthogonality) and if i=j this product is equal to 1 (the columns are unit vectors), then
E) Consider S={e_1,0}. S is orthogonal but is not linearly independent, because 0∈S.
In fact, every orthogonal set in R^n without zero vectors is linearly independent. Take a orthogonal set
and suppose that there are coefficients a_i such that
. For any i, take the dot product with u_i in both sides of the equation. All product are zero except u_i·u_i=||u_i||. Then
then
.