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QveST [7]
3 years ago
8

HELPPP ASAPPP!!!!!!!!

Mathematics
2 answers:
kaheart [24]3 years ago
7 0

Answer:

M

Step-by-step explanation:

3241004551 [841]3 years ago
7 0
The measure of what?
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Pls tell me some answers for this
devlian [24]

Answer:

∠B ≈ 56.25°

Step-by-step explanation:

Since the triangle is right use the cosine ratio to solve for B

cosB = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{5}{9}, thus

B = cos^{-1}(\frac{5}{9} ) ≈ 56.25°

3 0
3 years ago
Read 2 more answers
-36 ÷ 4 A) 4 groups of 9 negatives B) 4 groups of 9 positives C) 9 groups of 4 negatives D) 9 groups of 4 positives
Valentin [98]

Answer:

A) 4 groups of 9 negatives

Step-by-step explanation:

-36/4

-9

This means we have 4 groups of 9 negatives

7 0
3 years ago
In a normal distribution, 95% of the data fall within how many standard deviations of the mean? O A. Three standard deviations B
Galina-37 [17]

Answer:

Two standard deviations

Step-by-step explanation:

The Z score is obtained using the mean and standard deviation, according to the empirical. Rule, which gives percentage of values that lie within an interval estimate in a normal distribution ;

one standard deviation lie within 68% of the mean

Two standard deviations lie within 95%

Three standard deviations lie within 99.7%

Hence, for the question given, 95% fall within 2 standard deviations of the mean

4 0
2 years ago
A certain medical test is known to detect 73% of the people who are afflicted with the disease Y. If 10 people with the disease
Setler [38]

The probability of an event is the measurement of the chance of that event's occurrence. The probabilities of considered events are:

  • P(At least 8 have the disease) ≈ 0.4378
  • P(At most 4 have the disease)  ≈ 0.0342
<h3 /><h3>How to find that a given condition can be modeled by binomial distribution?</h3>

Binomial distributions consist of n independent Bernoulli trials. Bernoulli trials are those trials that end up randomly either on success (with probability p) or on failures( with probability 1- p = q (say))

Suppose we have random variable X pertaining to a binomial distribution with parameters n and p, then it is written as

X = B(n,p)

The probability that out of n trials, there'd be x successes is given by

P(X=x)  = ^nC_xp^x(1-p)^{n-x}

Since 10 people can be either diseased or not and they be so independent of each other (assuming them to be selected randomly) , thus, we can take them being diseased or not as outputs of 10 independent Bernoulli trials.

Let we say

Success= Probability of a diseased person tagged as diseased by the clinic

Failure = Probability of a diseased person tagged as not diseased by the clinic.

Then,

P(Success) = p = 72% = 0.72 (of a single person)

P(Failure) = q = 1-p = 0.28

Let X be the number of people diagnosed diseased by the clinic out of 10 diseased people. Then we have: X ≈ B(n+10,P=0.73)

Calculating the needed probabilities, we get:

a) P(At leased 8 have disease) = P(X≥8) =P(X=8) + P(X=9) + P(X=10)

P(X≥8) = ^{10}C_8(0.73)^8(0.28)^2+^{10}C_9(0.73)^9(0.27)^1+^{10}C_{10}(0.73)^{10}(0.27)^0

P(X≥8) ≈ 0.2548 + 0.1456 + 0.0374 ≈ 0.4378

b)  P(At most 4 have the disease) = P(X≤4) = P(X=0) + P(X=1)+P(X=2)+P(X=3)+P(X=4)

P (X ≤ 4) =

^{10}C_0(0.73)^0(0.27)^{10}+^{10}{C_1(0.73)^1(0.27)^9+^{10}{C_2(0.73)^2(0.27)^8+^{10}C_3(0.73)&^3(0.27)^7 \\

+^{10}C_4(0.73)^4(0.27)^6

P (X ≤ 4) = 0.000003 + 0.000076+0.00088+0.00604+0.02719

P (X ≤ 4) =  0.0342

Thus,

The probabilities of considered events are:

  • P(At leased 8 have disease) = 0.4378 approx
  • P(At most 4 have the disease)  = 0.0342 approx

Learn more about binomial distribution here:

brainly.com/question/13609688

#SPJ1

4 0
2 years ago
Find the slope of a line given the following two points: (4, 3) and (5, 2). 1, -1, 2, -2
Mars2501 [29]
The slope formula is y2-y1/ x2-x1 so after plugging it in it would be 2-3/5-4 and you will get your answer.
8 0
3 years ago
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