A function
is periodic if there is some constant
such that
for all
in the domain of
. Then
is the "period" of
.
Example:
If
, then we have
, and so
is periodic with period
.
It gets a bit more complicated for a function like yours. We're looking for
such that
Expanding on the left, you have
and
It follows that the following must be satisfied:
The first two equations are satisfied whenever
, or more generally, when
and
(i.e. any multiple of 4).
The second two are satisfied whenever
, and more generally when
with
(any multiple of 10/7).
It then follows that all four equations will be satisfied whenever the two sets above intersect. This happens when
is any common multiple of 4 and 10/7. The least positive one would be 20, which means the period for your function is 20.
Let's verify:
More generally, it can be shown that
is periodic with period
.
Answer:
A = 236,000 (1.04)^t
population in 2009 : 335,902 people
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form) = 4/100 = 0.04
t= years passed from 2000
A = population after t years
Replacing with the values given:
A = 236,000 (1+ 0.04)^t
A = 236,000 (1.04)^t
Population in 2009.
t = 2009-2000 = 9
A = 236,000 (1.04)^9
A = 335,902 people
Feel free to ask for more if needed or if you did not understand something.
Answer: x + 100
Step-by-step explanation:
From the question, we are told that Bobbie has 100 more followers than Debora and x is used to represent the number of followers that Debora has.
The expression that shows the number of followers Bobbie has will be the number of followers that Debora has plus 100. This will be :
= x + 100
To multiply whole numbers and fractions, multiply the numerator by the whole number. Example: 1/3×4= 4/3=1 1/3
Answer:
The restaurant Manager can afford 6 employees for the day.
Step-by-step explanation:
Manager can spend at most of $400.
Total Money ≤ $400
Cost to operate bank = $100
Cost for each employee = $50
Let number of employees for the day be
Hence the equation will become;
Solving this equation we get;
Hence, The restaurant Manager can afford 6 employees for the day.