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Alenkasestr [34]
3 years ago
6

A soccer ball has a wholesale price of $14 and is marked up 115% before it is sold. If Joe purchases the soccer ball with a 5.5%

sales tax, how much will he pay in total?
Mathematics
2 answers:
GalinKa [24]3 years ago
8 0

Answer:

$31.76

Step-by-step explanation:

Original (wholesale) price:  $14

Markup:  (1.15)($14) = $16.10

Marked up price:  (1.00 + 1.15)($14) = (2.15)($14) = $30.10

Total price (including tax):  (1.055)($30.10) = $31.76

Romashka [77]3 years ago
5 0

Answer:

22.47

Step-by-step explanation:

155%+5.5%=160.5%  

14x160.5%=22.47 is the total payment.

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The sequence -11, -5, 1...... is an arithmetic
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Answer:

25, 31, 37

Step-by-step explanation:

1 2 3 4 5 6 7 8 9 10

-11 -5 1 7 13 19 25 31 37 43

6 6 6 6 6 6 6 6 6

25 + 31 + 37 = 93

7 0
3 years ago
Y = -17.5x + 2.7x + 14.1 - 11.9x
slava [35]

Answer:

y=-26.7x+14.1

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Step-by-step explanation:

8 0
3 years ago
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Use algebraic rules of equations to predict the solution to the system of equations. Include all of your work for full credit.
bezimeni [28]
Use substitution
x+(2x-1)=-4
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7 0
3 years ago
the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume
zhuklara [117]
Given:
Population proportion, \mu _{p} = 57% = 0.57
Population standard deviation, σ  = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
SE_{p} =  \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783

The confidence interval is 
\hat{p} \pm z^{*}SE_{p}
where
\hat{p} = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
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Answer: Between 0.417 and 72.4), or between (41% and 72%)

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