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enot [183]
3 years ago
12

When nitrogen dioxide (NO2) from car exhaust combines with water in the air, it forms nitric acid (HNO3), which causes acid rain

, and nitrogen oxide.Write the balanced chemical equation.How many moles of HNO3 are produced from 0.292 mole of H2O
Chemistry
1 answer:
Gekata [30.6K]3 years ago
5 0

Answer:

n_{HNO_3}=0.584molHNO_3

Explanation:

Hello.

In this case, given the described reaction, the formation of nitric acid turns out:

NO_2+H_2O\rightarrow HNO_3

Since two hydrogen atoms are present at the reactants we balance it as follows:

3NO_2+H_2O\rightarrow 2HNO_3+NO

In such a way, since there is a 1:2 mole ratio between water and nitric acid, the produced moles of nitric acid, turns out:

n_{HNO_3}=0.292molH_2O*\frac{2molHNO_3}{1molH_2O}\\\\ n_{HNO_3}=0.584molHNO_3

Best regards!

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Answer:

adding 750 grams of water at 60° Celsius .

Explanation:

  • We can calculate the amount of heat lost from  750 grams of water at 80°C to be lowered by 10°C using the relation:

<em>Q = m.c.ΔT,</em>

Where, Q is the amount of heat lost by water (Q = ??? J).

m is the mass of water (m = 750.0 g).

c is the specific heat capacity of the water (c = 4.18 J/g.°C).

ΔT is the temperature difference (ΔT = final T - initial T = - 10.0°C, the temperature of water is lowered by 10.0°C).

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(- 10.0°C) = - 31350.0 J = -31.350 kJ.

Now, we can calculate the Q that is gained by the different added amounts of water:

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ΔT = 70.0°C - 50.0°C = 20.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(20.0°C) = 62700.0 J = 62.70 kJ.

  • <em>adding 325 grams of water at 60° Celsius :</em>

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (325.0 g)(4.18 J/g.°C)(10.0°C) = 13585.0 J = 13.585 kJ.

  • <em>adding 750 grams of water at 60° Celsius :</em>

ΔT = 70.0°C - 60.0°C = 10.0°C,

∴ Q = m.c.ΔT = (750.0 g)(4.18 J/g.°C)(10.0°C) = 31350.0 J = 31.350 kJ.

  • <em>adding 1000 grams of water at 55° Celsius:</em>

ΔT = 70.0°C - 55.0°C = 15.0°C,

∴ Q = m.c.ΔT = (1000.0 g)(4.18 J/g.°C)(15.0°C) = 62700.0 J = 62.70 kJ.

  • So, the right choice is:

<em>adding 750 grams of water at 60° Celsius</em>

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