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padilas [110]
3 years ago
14

How would you determine the proper number of significant figures for measurement of a liquid using a graduated cylinder?

Chemistry
1 answer:
Veronika [31]3 years ago
4 0
You get ur answer
Ex: 4.5
And put a rounding number at the end/uncertain digit
Ex: 4.50
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Arrange carbon, phosphorus and sulfur in order of reactivity to write their reaction with oxygen.
mihalych1998 [28]

Answer:

Solid phosphorus reacts with gaseous oxygen to produce solid diphosphorus pentaoxide. ... Methanol burns in oxygen to produce carbon dioxide gas and water vapor.

Explanation:

Solid phosphorus reacts with gaseous oxygen to produce solid diphosphorus pentaoxide. ... Methanol burns in oxygen to produce carbon dioxide gas and water vapor.

6 0
2 years ago
BaCl2(aq) + Na2CO3(aq) BaCO3(s) + NaCl(aq
Vitek1552 [10]
This is the equation balanced:

<span>BaCl2(aq) + Na2CO3(aq) = BaCO3(s) + 2 NaCl(aq)

Then the coefficient in front of Na Cl is 2.

Answer: 2
</span>


7 0
3 years ago
Its gelatin and a fruit cup the same (its for a project)
gizmo_the_mogwai [7]

Answer:

No

Explanation:

Gelatin is a substance that makes jello, and a fruit cup is a cup full of fruit

6 0
3 years ago
Read 2 more answers
When a 2.00 g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 1.28 kJ ⋅ K − 1 , the tempe
Alchen [17]

Answer : The molar heat of solution of KCl is, 17.19 kJ/mol

Explanation :

First we have to calculate the heat of solution.

q=c\times (\Delta T)

where,

q = heat produced = ?

c = specific heat capacity of water = 1.28kJ/K

\Delta T = change in temperature = 0.360 K

Now put all the given values in the above formula, we get:

q=1.28kJ/K\times 0.360K

q=0.4608kJ=460.8J

Now we have to calculate the molar heat solution of KCl.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = ?

q = heat released = 460.8 J

m = mass of KCl = 2.00 g

Molar mass of KCl = 74.55 g/mol

\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{2.00g}{74.55g/mole}=0.0268mole

Now put all the given values in the above formula, we get:

\Delta H=\frac{460.8J}{0.0268mole}

\Delta H=17194.029J/mol=17.19kJ/mol

Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol

7 0
3 years ago
Pls answer with a passion and a goal of smartness
Svetach [21]

Answer:

b

Explanation:

I used my passion and skill for learning to do a quick google search :P

7 0
3 years ago
Read 2 more answers
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