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Zielflug [23.3K]
3 years ago
8

Bryan threw a tennis ball into the air. The ball hit the ground and bounced once before landing in a mud puddle. Which graph bes

t models the height of the ball over time?
Mathematics
1 answer:
Mashcka [7]3 years ago
8 0

Answer: A child tosses a tennis ball into the air and it lands in the mud. The function h(t)=−16t2+16t+4

h

(

t

)

=

−

16

t

2

+

16

t

+

4

h(t)=−16t

2

+16t+4 gives the ball's height in feet with respect to time in seconds. a. Sketch a graph of y = h(t). Highlight the portion of the curve that fits this situation. b. What is happening to the height of the tennis ball with respect to the time? c. Since velocity is a function of distance traveled overtime, what part of the graph represents the velocity of the ball? What is happening to the velocity of the tennis ball with respect to time? d. Copy and complete the following table of time (s) versus height (ft). $$\begin{matrix}\text{t (s)} & \text{0} & \text{0.25} & \text{0.5} & \text{0.75} & \text{1} & \text{1.25} & \text{1.50}\\text{h (ft)} & \text{} & \text{} & \text{} & \text{} & \text{} & \text{} & \text{_}\\end{matrix}$$ e. Use the table to determine the ball's average velocity in ft/sec for each 0.25-second time interval. f. Predict the velocity of the ball at t = 0.8 seconds. Be prepared to justify your answer to the class.

Step-by-step explanation:

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WILL GIVE BRAINLIEST. Need an answer ASAP!
Ksivusya [100]

Answer:

BE=12 units

Step-by-step explanation:

We\ know\ that,\\In\ a\ rectangle\ all\ diagonals\ are\ equal\ and\ bisect\ each\ other.\\Hence,\\In\ Rectangle\ ABCD,\\AE=EC\\Hence,\\Substituting\ the\ values\ we\ get:\\x+4=3x-12\\Hence,\\-2x=-16\\x=\frac{-16}{-2}=8\\Now,\\We\ also\ know\ that,\\ AC=DB\\Hence,\\\frac{AC}{2}=\frac{DB}{2} \\Hence,\\DE=EB=AE=EC\\Hence,\\Since\ AE=BE,\\BE=x+4\\We\ already\ know\ that\ x=8.\\Hence, BE=8+4=12

8 0
2 years ago
Find the surface area of the triangular prism
lesya692 [45]

The surface area of the triangular prism is 1664 square inches.

Explanation:

Given that the triangular prism has a length of 20 inches and has a triangular face with a base of 24 inches and a height of 16 inches.

The other two sides of the triangle are 20 inches each.

We need to determine the surface area of the triangular prism.

The surface area of the triangular prism can be determined using the formula,

SA= bh+pl

where b is the base, h is the height, p is the perimeter and l is the length

From the given the measurements of b, h, p and l are given by

b=24 , h= 16 , l=20 and

p=20+20+24=64

Hence, substituting these values in the above formula, we get,

SA= (24\times16)+(64\times20)

Simplifying the terms, we get,

SA=384+1280

Adding the terms, we have,

SA=1664 \ square \ inches

Thus, the surface area of the triangular prism is 1664 square inches.

6 0
3 years ago
Ht) = -16t+32t+ 10.​
KonstantinChe [14]
Answer:
16t + 10

Explanation:
Step 1 - Add like terms

-16t + 32t + 10
16t + 10
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%2064%2F4" id="TexFormula1" title="\sqrt{x} 64/4" alt="\sqrt{x} 64/4" align="abs
ozzi

Answer: =16\sqrt{x}

Step-by-step explanation:

\sqrt{x}\frac{64}{4}=16\sqrt{x}

8 0
2 years ago
I need help I’m bad at math
Alina [70]
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].

The width of each rect. is 1/2.

The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.

The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:

{1.875, 2.5, 2.875}

Add these three areas together; you sum will represent the approx. area under the given curve on the given interval:  1.875+2.5+2.875 = ?
5 0
3 years ago
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