The vertices of AABC are A(-4,4), B(-2,2), and C(-5,2). If AABC is reflected across the line
1 answer:
You might be interested in
To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0