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Karo-lina-s [1.5K]
3 years ago
5

4x + 6 -x = 2x +3 NEED HELP FASTT!

Mathematics
1 answer:
jeyben [28]3 years ago
5 0

Answer:

If you are finding the amount for the variable x, then the answer is -3.

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One equation in a system of linear equations is y=2x+1
Rufina [12.5K]

Step-by-step explanation:

<u>Given equation:</u>

  • y = 2x + 1

a. write a second equation so that (1,3) is the only solution of the system

To have only one solution the equation must have a different slope.

<u>Let it be 10, then the y-intercept of y = 10x + b is:</u>

  • 3 = 1*10 + b ⇒ b = -7

<u>And the equation:</u>

  • y = 10x - 7

b. Write a second equation so that the system has infinitely many solutions

<u>To have infinitely many solutions, both equations must be same:</u>

  • y = 2x + 1

c. Write a second equation so that the system has no solutions.

<u>To have no solutions, the equations must have same slope but different y-intercepts:</u>

  • y = 2x + 5
3 0
3 years ago
La profesora de matemáticas solicita a dos estudiantes que describan las cosas que les han parecido interesantes de los números
Makovka662 [10]

Answer:

Respuesta D

Step-by-step explanation:

Paola afirma: Todo número compuesto par, se puede escribir como la multiplicación de factores primos.

Esta afirmación es cierta, pues es un caso  de la afirmación de que todo número natural mayor que uno se puede escribir como multiplicación de números primos. A este proceso se le llama descomposición en factores primos.

Edwin afirma: Todo número compuesto impar se puede escribir como la suma de dos números primos.

Esta afirmación es falsa. Note que al sumar dos números impares de la forma 2k+1 y 2m+1 para k distinto de m, se obtiene

2k+1+2m+1 = 2(km+1)

Es decir, la suma de dos números impares es siempre par.

Note que a excepción de 2, todo número primo es impar. Para que esta afirmación fuera cierta, necesariamente tendría que pasar que cualquier número impar k se escriba de la forma p+2 donde p es un número primo. Esto es equivalente que para cualquier número impar k, el número k-2 sea primo.

Basta con dar un ejemplo para ver que esto no pasa. Tomemos k=11. En este caso, k-2 = 9, el cuál no es un número primo. Entonces 11 no se puede  descomponer como la suma de dos números primos.

5 0
4 years ago
Helpppppppppppppppppppp
Sloan [31]

Answer:

Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

Step-by-step explanation:

We need to find sum of \frac{7x}{x^2-4} and \frac{2}{x+2}

Finding sum of  \frac{7}{x^2-4} and \frac{2}{x+2}:

\frac{7x}{x^2-4}+\frac{2}{x+2}

We know that x^2-4 =(x+2)(x-2)

Replacing x^2-4

\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}

So, Sum of \frac{7x}{x^2-4} and \frac{2}{x+2} is \mathbf{\frac{9x-4}{x^2-4}}

Option B is correct answer.

6 0
3 years ago
-6(-v^3-3+5x^2)<br><br> use the distributive property to remove parentheses<br><br> Help!
Ad libitum [116K]
-6 (-v^3 - 3 + 5x^2) =
6v^3 + 18 - 30x^2 <==
8 0
4 years ago
Please explain how you got the answers also please. Thank you :)
Umnica [9.8K]

Answer:

x = -2 —> y = 4

x= 0 —> y = 1

x= 3 —> y = 1/8

Step-by-step explanation:

<h3>X= –2</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ - 2}  =(  \frac{2}{1} ) ^{2}  =  {2}^{2}  = 4

<h3>X= 0</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ 0}  =1

<h3>X= 3</h3>

y = ( \frac{1}{2} ) ^{x}  \\ y = ( \frac{1}{2} ) ^{ 3}  =  \frac{ {1}^{3} }{ {2}^{3} } =  \frac{1}{8}

I hope I helped you^_^

7 0
3 years ago
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