Question

SU and VT are chords that intersect at point R. A circle is shown. Chords S U and V T intersect at point R. The length of S R is x + 6, the length of R U is x, the length of V R is x + 1, and the length of R T is x + 4. What is the length of line segment VT? 4 units 8 units 13 units 14 units

Answer 1

Answer:

13units

Step-by-step explanation:

If SU and VT are chords that intersect at point R, then;

SR/RT = VR/RU and VT = VR + RT

Given the following

SR= x+6

RU = x

VR = x+1

RT = x+4

Substitute into the expression above;

x+6/x+4 = x+1/x

Cross multiply

x(x+6) = (x+1)(x+4)

Expand

x^2+6x = x^2+4x+x+4

x^2+6x = x^2+5x+4

x^2 will cancel out from both sides

6x = 5x+4

6x-5x = 4

x = 4

Get VT

VT = VR + RT

VT = x+1 + x+4

VT = x+x+1+4

VT = 2x+5

Since x = 4

VT = 2(4) + 5

VT = 8+5

VT= 13 units

Hence the length of the line VT is 13units

Answer 2

Answer: just so you have proof my homie above is correct

Step-by-step explanation:

got it right on edge