Answer:
third one
Step-by-step explanation:
No it has length breadth/width and height
Answer:
There are 3 zeros, which are:

Step-by-step explanation:
Given the function

To get the zeros of
, set
or 
so

as

so

Using the zero factor principle:

so

solving



Therefore, there are 3 zeros, which are:

Hello!
To find our answer, we first convert 1/2 into fourths. We multiply it by 2/2, giving us 2/4.
2/4+1/4=3/4
Therefore, our answer is
.
I hope this helps!
Answer:
70% of the meeting is left.
Step-by-step explanation:
Hi, to answer this question, first, we have to convert the hours to minutes.
Since 1 hour = 60 minutes
For 2 hours:
1 /60 = 2/x
x = 2 (60)
x = 120 minutes
So, a scout meeting last 120 minutes (2 hours)
36 minutes already spent.
120-36 = 84 minutes left
So, if 120 is the 100% of the meeting, for 84 minutes:
120/100 = 84/x
1.2 =84/x
x = 84/1.2
x = 70%
70% of the meeting is left.