Answer:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of 
.
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.
This means that 
95% confidence level
So 
, z is the value of Z that has a p-value of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).
What do you need to know?
A=p(1+i/m)^mn
A=980×(1+0.08÷4)^(4×5)
A=1,456.23
So firstly, let's figure out the expression for a singular goody bag. Since there's 2 of each item, a single goody bag is going to be 
Now since we have 7 friends who are all getting 1 goody bag, multiply the cost of the goody bag by 7, and our expression is 
. Now we can solve it from there.
Firstly, solve the multiplication inside the parentheses: 
Now add up what's inside the parentheses: 
Lastly, multiply and <u>your answer will be $56.56</u>
Answer:
714
Step-by-step explanation:
So lets go over what we know.
The bus only goes for 6 hours each day.
So lets just think of a full day as 6 hours.
Each day(6 hours), 4284 passangers ride the bus.
To find passangers per hour, we must divide the total passangers by the total hours.
This is 4284(total passangers) divided by 6(total hours):
4284/6
=
714
So each hour, there are 714 passangers.
Hope this helps!
