2 years ago

"Which expression stands for "32 more than a number d"?"

2 answers:

8 0

Answer: I believe that the answer is C, 32+d.

Explanation: if you were trying to get 32 more than a number you would add the number plus the variable.

I hope this helps! ^^

kogti [31]2 years ago

3 0

Answer:

32+d

Step-by-step explanation:

because it's asking for 32 added on to whatever d is

example

if d=5 it would be asking what's 32 +5

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If a 30-60-90 right triangle has a hypotenuse 6, what is the length of the short leg?

Anton [14]

Answer:

$\sqrt[3]{3}$

Step-by-step explanation:

use the Pythagoras Theorem

Since you have the hypotenuse (6"), just go backwards. 62 = 36 = a2 + b2.

6 0

2 years ago

What mathematical question can we ask

lilavasa [31]

Be specific please!!!

5 0

3 years ago

The longer leg of a right triangle is 6cm longer than the shorter leg and also 1cm longer than the hyptenese. find the perimeter

CaHeK987 [17]

X - a leg (x > 6);
x - 6 - a leg;
x + 1 - a hypotenuse;
Use the Pythagorean theorem
$(x+1)^2=x^2+(x-6)^2$

Use: $(a\pm b)^2=a^2\pm2ab+b^2$

$x^2+2x+1=x^2+x^2-12x+36\ \ \ |-x^2-2x-1\\\\x^2-14x+35=0\ \ \ |-35\\\\x^2-14x=-35\\\\x^2-2\cdot x\cdot7=-35\ \ \ |+7^2\\\\x^2-2\cdot x\cdot7+7^2=-35+7^2\\\\(x-7)^2=14\iff x-7=\pm\sqrt{14}\ \ \ |+7\\\\x=7-\sqrt{14} < 6;\ x=7+\sqrt{14}$

$x=7+\sqrt{14}\\x-6=1+\sqrt{14}\\x+1=8+\sqrt{14}$

The perimeter:

$7+\sqrt{14}+1+\sqrt{14}+8+\sqrt{14}=16+3\sqrt{14}$

5 0

3 years ago

(x + 20 Solve for x: 2 = 3x Ox= 10 Ox=4 Ox=-14 Ox=-17

maxonik [38]

Answer:

$\pmb{x=10 }$