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ruslelena [56]
3 years ago
8

3x - 12 = 3x + 1 help please

Mathematics
1 answer:
Yakvenalex [24]3 years ago
3 0

Answer:

There's no solution to this equation, when 2 equations have the same slope but different y-intercepts, they're parallel. This means they never intercept and there is NO solution and we can't solve for x.

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To meet your goal for selling raffle tickets, you must meet the inequality t ≥ 15. If you sold 16 tickets, did you reach your go
Softa [21]
Yes because 16 is greater than 15 and it has to be greater or equal to 15
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3 years ago
Which of the following graphs would not represent the relative frequencies of heads when tossing 1 penny?
tiny-mole [99]

Answer:

the chance of getting heads when flipping a coin is 50%. As I cannot see the graphs, choose the one that shows 50%.

3 0
3 years ago
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100 points + Brainy<br><br> Math help please
aev [14]

Answer:

Q = -6

Step-by-step explanation:

To find the answer to this, you first must multiply the first function by 2:

2 x (x - 3y = 4)

2x - 6y = 8

Which then means that the second function is the same. This means that to find Q you need to find the number that changed +Qy into -6:

2x - 6y = 8

2x + Qy = 8

The 2x's cancel out, and then remove the equals and the 8:

-6y = Qy

<h3>So Q must be -6</h3>
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5 0
4 years ago
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Find the product of 2r^2(6r^3+14r^2-30r+14)
mylen [45]

Answer:

<em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r² </em>

Step-by-step explanation:

a(b ± c) = ab ± ac (distributive property)

a^{m} * a^{n} = a^{m+n}

2r²(6r³ + 14r² - 30r + 14) = <em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r²</em>

6 0
3 years ago
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Write an expression for the area of a triangle with a height of 2x^2 units and a base of 5x^2+4x units
Stolb23 [73]

Answer:

The area of the triangle is 5x^4 + 4x^3 square units

Step-by-step explanation:

Given

Shape: Triangle

Height = 2x^2

Base = 5x^2+4x

Required

The area of the triangle

The area of a triangle is calculated as thus;

Area = \frac{1}{2}(base)(height)

By substituting Height = 2x^2 and Base = 5x^2+4x; This gives

Area = \frac{1}{2}(5x^2 + 4x)(2x^2)

Area = \frac{(5x^2 + 4x)(2x^2)}{2}

Area = (5x^2 + 4x)(x^2)

Open Bracket

Area = 5x^2 * x^2 + 4x * x^2

Area = 5x^4 + 4x^3

Hence, the area of the triangle is 5x^4 + 4x^3 square units

3 0
3 years ago
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