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bagirrra123 [75]
2 years ago
14

Find the product of 2r^2(6r^3+14r^2-30r+14)

Mathematics
2 answers:
steposvetlana [31]2 years ago
8 0

Answer: 2r2(6r3+14r2−30r+14)

Step-by-step explanation:

Apply the distributive property

2r2(6r3)+2r2(14r2)+2r2(−30r)+2r2⋅14

Simplify

2⋅6(r2r3)+2⋅14(r2r2)+2⋅−30(r2r)+28r2

Simplify each term

12r5+28r4−60r3+28r2

mylen [45]2 years ago
6 0

Answer:

<em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r² </em>

Step-by-step explanation:

a(b ± c) = ab ± ac (distributive property)

a^{m} * a^{n} = a^{m+n}

2r²(6r³ + 14r² - 30r + 14) = <em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r²</em>

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Answer:

11

Step-by-step explanation:

22 is the largest number you are given in this diagram. 0 is the smallest. that would be your first step.

Next think about it as if you already know your midpoint, as in, midpoint being half of your ending value.

Lastly, you want to divide 22 in half, since midpoint is half of your line segment, and then answer you get is 11

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What is these decimal numbers from least to greatest
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Least to Greatest:
1.037, 1.073, 1.37, 1.703
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{HIGH PAYOUT} Can someone help by showing work on how to get to answer?
Gala2k [10]

Let's assume each line is one toothpick.

In figure 1, there is a square made out of the 4 toothpicks.

In figure 2, there are four squares made. However, the 4 four toothpicks were already used, so we don't count them twice. That gives 4 (that were used) + 3 (the new ones on the left) + 3 (new ones on top) + 3 (new ones on right). We sum them up: 4 + 3 + 3 + 3 = 13.

In figure 3 there are nine squares made. We have the 13 squares made, plus 3 on the left column, 2 on the left center column, 3, on the center column, 2 on the right center, and 3 on the right. We total them up. 13 + 3 + 2 + 3 + 2+ 3 = 26.

Let's look at the pattern.

<u>Figure #</u> <u># Toothpick</u>s

1 4

2 13

3 26

From figure 1 to 2, we added 9. From 2 to 3 we added 13. If we draw figure 4, we would add (from left to right) 3, 2, 2, 3, 2, 2, 3. That would be 17 toothpicks added, and 39 total. Let's go back to the table.

<u>Figure #</u> <u># Toothpick</u>

1 4

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Now let's look at the sequence happening. As we add more, we increase by 9, then 13, then 17. For each row, we add the same number as the previous row and then add 4. Drawing Figure 5 would be too much, but we can conclude based on the pattern that 21 squares would be added. We can take this sequence as far as we need to. We want the 10th figure or term, so we apply the pattern and keep going until we get there.

<u>Figure #</u> <u># Toothpick</u>

1 4

2 13 <--- add 9

3 26 <--- add 13, the same 9 and 4 more

4 39 <--- add 17, the same 13 and 4 more

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6 85 <-- add 25, the same 21 and 4 more

7 114 <-- add 29, the same 25 and 4 more

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9 184 <---- add 37

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Thus the 10th figure has 225 toothpicks.

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