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bagirrra123 [75]
3 years ago
14

Find the product of 2r^2(6r^3+14r^2-30r+14)

Mathematics
2 answers:
steposvetlana [31]3 years ago
8 0

Answer: 2r2(6r3+14r2−30r+14)

Step-by-step explanation:

Apply the distributive property

2r2(6r3)+2r2(14r2)+2r2(−30r)+2r2⋅14

Simplify

2⋅6(r2r3)+2⋅14(r2r2)+2⋅−30(r2r)+28r2

Simplify each term

12r5+28r4−60r3+28r2

mylen [45]3 years ago
6 0

Answer:

<em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r² </em>

Step-by-step explanation:

a(b ± c) = ab ± ac (distributive property)

a^{m} * a^{n} = a^{m+n}

2r²(6r³ + 14r² - 30r + 14) = <em>12 </em>r^{5}<em> + 28 </em>r^{4}<em> - 60 r³ + 28 r²</em>

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

a.P(E_1/A)=0.0789

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Step-by-step explanation:

Let E_1,E_2,E_3 are the events that denotes the good drive, medium drive and poor risk driver.

P(E_1)=0.30,P(E_2)=0.50,P(E_3)=0.20

Let A be the event that denotes an accident.

P(A/E_1)=0.01

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P(A/E_3)=0.10

The company sells Mr. Brophyan insurance policy and he has an accident.

a.We have to find the probability Mr.Brophy is a good driver

Bayes theorem,P(E_i/A)=\frac{P(A/E_i)\cdot P(E_1)}{\sum_{i=1}^{i=n}P(A/E_i)\cdot P(E_i)}

We have to find P(E_1/A)

Using the Bayes theorem

P(E_1/A)=\frac{P(A/E_1)\cdot P(E_1)}{P(E_1)\cdot P(A/E_1)+P(E_2)P(A/E_2)+P(E_3)P(A/E_3)}

Substitute the values then we get

P(E_1/A)=\frac{0.30\times 0.01}{0.01\times 0.30+0.50\times 0.03+0.20\times 0.10}

P(E_1/A)=0.0789

b.We have to find the probability Mr.Brophy is a medium driver

P(E_2/A)=\frac{0.03\times 0.50}{0.038}=0.395

c.We have to find the probability Mr.Brophy is a poor driver

P(E_3/A)=\frac{0.20\times 0.10}{0.038}=0.526

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