3 years ago

Find the product of 2r^2(6r^3+14r^2-30r+14)

Mathematics

2 answers:

steposvetlana [31]3 years ago

8 0

Answer: 2r2(6r3+14r2−30r+14)

Step-by-step explanation:

Apply the distributive property

2r2(6r3)+2r2(14r2)+2r2(−30r)+2r2⋅14

Simplify

2⋅6(r2r3)+2⋅14(r2r2)+2⋅−30(r2r)+28r2

Simplify each term

12r5+28r4−60r3+28r2

mylen [45]3 years ago

6 0

Answer:

12 $r^{5}$ + 28 $r^{4}$ - 60 r³ + 28 r²

Step-by-step explanation:

a(b ± c) = ab ± ac (distributive property)

$a^{m} * a^{n} = a^{m+n}$

2r²(6r³ + 14r² - 30r + 14) = 12  $r^{5}$  + 28  $r^{4}$  - 60 r³ + 28 r²

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