The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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Answer: 8x+12
Distribute the 4. So, 4(2x)+4(3). Then you end up with 8x+12.
Answer: First, draw and label a number line. Then plot the five values that are given above the line. Draw a box from the lower quartile to the upper quartile, with a line dividing it at the median. Then draw lines from the minimum and maximum values connecting to the box to form the whiskers.
Answer:
63 students.
Step-by-step explanation:
x students.
34 have science 28 have math 5 math and science 6 neither.
6 neither means there were at least 6 students so our number goes up to 6 students.
34 have science 28 have math 5 have both.
34-5 and 28-5
29 and 23
29+23 is 52 +5 is 57 +6 is 63.
63 students.
HOpe this helps!
Merry Christmas!
Well I would say the answer to your question is
A why?
well because -4 times -2 equals Positive 8 BUT if you times 8 by negative 1 it turns it back into a negative number!
Hope this helps
