Answer:
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
Step-by-step explanation:
We are given that the average human gestation period is 270 days with a standard deviation of 9 days. The period is normally distributed.
Firstly, Let X = women's gestation period
The z score probability distribution for is given by;
Z =
~ N(0,1)
where,
= average gestation period = 270 days
= standard deviation = 9 days
Probability that a randomly selected woman's gestation period will be between 261 and 279 days is given by = P(261 < X < 279) = P(X < 279) - P(X
261)
P(X < 279) = P(
<
) = P(Z < 1) = 0.84134
P(X
261) = P(
) = P(Z
-1) = 1 - P(Z < 1)
= 1 - 0.84134 = 0.15866
<em>Therefore, P(261 < X < 279) = 0.84134 - 0.15866 = 0.68</em>
Hence, probability that a randomly selected woman's gestation period will be between 261 and 279 days is 0.68.
(2x² + 7x + 10) - (x² + 2x - 9) =
2x² + 7x + 10 - x² - 2x + 9 =
x² + 5x + 19
Answer:
2/3<9/10; I used 3/4 as a benchmark.
Step-by-step explanation:
2/3<1/2; I used 1/2 as a benchmark.
2/3 = 0.(20/3) = 0.667
1/2 = 0.(10/2) = 0.5
So this is wrong, as 0.667 > 0.5.
1/2=3/5; I used 1/4 as a benchmark.
1/2 = 0.(10/2) = 0.5
3/5 = 0.(30/5) = 0.6
0.5 != 0.6, so this is wrong.
2/3<9/10; I used 3/4 as a benchmark.
2/3 = 0.(20/3) = 0.667
9/10 = 0.(90/10) = 0.9
So this is correct, as 0.667 < 0.9
3/4<2/3; I used 1/2 as a benchmark.
3/4 = 0.(30/4) = 0.75
2/3 = 0.(20/3) = 0.667
0.75 > 0.667, so this is wrong.
Answer:
1. X is added to 8
2. Subtract 14 by a number
3. Multiply 2 after you add 3 into a number.
4.. Twice a number plus 3
5. Divide 15 by a number
Step-by-step explanation: