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3 years ago

Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?

Mathematics

1 answer:

tiny-mole [99]3 years ago

5 0

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

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In a town election ,Azeem got 42 percent of the vote cast and Hamza get the remaining votes . If the total number of votes cast

sveta [45]

Answer:

23,200

Step-by-step explanation:

percentage of vote in favor of Azeem = 42

Since total percentage is 100

and Hamza got remaining percentage points

it can be calculated by subtracting Azeem's percentage of vote from total percentage

mathematically we have

percentage of vote in favor of Hamza = total percentage of vote - percentage of vote in favor of Azeem = 100 - 42 = 58

Therefore Hamza got 58% votes

Total no of votes cast as given in problem = 40,000

Vote for Hamza = 58% of total votes = 58% of 40000

=>Vote for Hamza = (58/100) * 40000 = 23,200.

Votes obtained by hamza is 23,200

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3 years ago

Merl needs to cut down 10.5 trees for every 5 cabins she builds

Anika [276]

10.5*5= 52.5 is the correct answer to the question

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3 years ago

Y=x² - 6x + 7 in quadratic vertex form (no need to show work)

ioda

Just use a calculator

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3 years ago

A carnival charges two different prices for admissions. Adults cost $4 while children cost $1.50. If a total of $5050 was collec

GenaCL600 [577]

Answer:

Step-by-step explanation:

We have to have 2 different equations to solve this. One equation will represent the number of tickets sold while the other represents the money collected when the tickets were sold.

We know that adult tickets + children tickets = 2200 tickets.

That's the "number of tickets" equation. Let's call adult tickets "a" and children's tickets "c". So a + c = 2200

Now if each adult costs $4, then the expression that represents that as a cost is 4a. If there is 1 adult, the cost is $4(1) = $4; if there are 2 adults, the cost is $4(2) = $8; if there are 3 adults, the cost is $4(3) = $12, etc.

The same goes for the children's tickets. If each child's ticket is $1.50, then the expression that represents the cost of a child's ticket is 1.5c (we don't need the 0 at the end; it doesn't change anything to drop it off). The total money brought in from the cost of these tickets was $5050, so

4a + 1.5c = 5050

Let's solve the first equation for a. If a + c = 2200, then a = 2200 - c. Sub that into the second equation and solve it for c:

4(2200 - c) + 1.5c = 5050 and

8800 - 4c + 1.5c = 5050 and

-2.5c = -3750 so

c = 1500

That means that there were 1500 children's tickets sold. If a + c = 2200, then a + 1500 = 2200 so

a = 2200 - 1500 so

a = 700

There were 1500 children's tickets sold and 700 adult tickets sold.

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3 years ago

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NISA [10]

Answer:

2,34x

Step-by-step explanation:

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2 years ago

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