I don’t even wanna go get my kids and get to go to work tomorrow so y’all don’t know what I gotta I wanna is the day you got me in my car so I’m going back home to you and get my kids done and then go to take my car to the house I gotta is a way I gotta is a time for I don’t even wanna go get my kids and get to go to work tomorrow so y’all don’t know what I gotta I wanna is the day you got me in my car so I’m going back home to you and get my kids done and then go to take my car to the house I gotta is a way I gotta is a time for
Answer:
20 degfress
Step-by-step explanation:
Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
My answer would be 8.. I may not be correct, but I tried. So, I placed the numbers from least to greatest and split it 1’s and 2’s VS 3’s and 4’s. I just added 1 plus 2 plus 2 and a half plus 2 and a half and got 8. I also added (3+3+3)+3 and a half plus 3
