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3 years ago

Find the principal (positive) square root of 22. if necessary, round the answer to the nearest hundredth (two decimal places).

Mathematics

1 answer:

4vir4ik [10]3 years ago

4 0

Step 1

Find the two perfect square numbers it lies between.

Solution:
4²= 16 and 5² = 25, so lies between 4 and 5.

step 2

Divide 22 by 4. 22/4 = 5.5 (you can round off your answer)

step 3

Average 5.5 and 4. (5.5+4)/2 = 4.75

step 4

repeat step 2

Divide 22 by 4.75. 22/4.75 = 4.6316

step 5

repeat step 3

Average 4.75 and 4.6316. (4.75+4.6316)/2 = 4.6908

the answer is

4.69

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8_murik_8 [283]

Answer:

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Step-by-step explanation:

23=4 3+4+7 1/2 4/7 8/2

6 0

2 years ago

Show me how to get this answer show your work

Rama09 [41]

We know that angle MKJ is comprised of angle MKL and angle LKJ. That means if we add MKL and LKJ, we should get 80 degrees, which is the measure of angle MKJ.

$MKL + LKJ= MKJ \implies \\ 2x+10+3x-5=80 \implies \\ 5x+5=80 \implies\\ 5x=75 \implies \\ x=15$

So, we know that our x is 15. That is not enough to tell whether KL is an angle bisector, because we have to evaluate both MKL and LKJ with x=15, so:

$MKL=2(15)+10 = 40\\ LKJ=3*15-5=40$

So we see that these two angles are actually bisectors, and the third question best describes this phenomenon.

6 0

3 years ago

Read 2 more answers

What is the correlation coefficient for the data shown in the table? 0 1 4 5

SOVA2 [1]

we know that

The correlation coefficient is a number between -1 and +1 that represent the linear dependence of two variables or sets of data

Using the function CORREL in a excel tool, calculate the correlation coefficient (r)

see the attached table

the correlation coefficient for the data in the table is equal to 1

therefore

the answer is

r=1

4 0

3 years ago

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Idk what all these means need help plzzzzzx

Schach [20]

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3 years ago

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The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-30}{2} = 1.5$ >0

P(X<33) = P( Z<1.5)

= 1- P(Z>1.5)

= 1 - ( 0.5 - A(1.5))

= 0.5 + 0.4232

P(X<33) = 0.9232

Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

$Z = \frac{33-26}{2} = 3.5$ >0

P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

= 0.5 - 0.4990

= 0.001

P(X>26) = 0.001

5 0

3 years ago