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Sliva [168]
3 years ago
14

Below are two parallel lines with a third line intersecting them

Mathematics
2 answers:
ANEK [815]3 years ago
4 0

Answer:

x = 122°

Step-by-step explanation:

Two parallel lines with a third line intersecting them are called a transversal.

The two angles shown in the picture, x and 122° are alternate interior angles.

Alternate angles are a pair of angles that are on the inner side of each of the two lines but are on opposite sides of a transversal.

These are really similar to vertically opposite angles!

All alternate angles have the same value, thus x = 122°.

You can also see that alternate angles are like corresponding angles and vertically opposite angles combined!

olga_2 [115]3 years ago
3 0

Answer:

x = 122

Step-by-step explanation:

x = 122 because of alternate interior angles

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It takes a car 1.75 h to go from mike marker 10 to mile marker 115. what is the average speed of the car?
Black_prince [1.1K]

Answer:

60 mph

Step-by-step explanation:


8 0
3 years ago
What is the absolute value -4/25???
andre [41]
Absolute value is a number's distance away from 0. So, all answers are positive. -4/25 is 4/25's away from 0, so your answer is -4/25. To clarify: if you have the absolute value of ANY number, it will always be the positive version of itself. 

8 0
3 years ago
the length of a rectangle is 2 in more than it's w i d t h the area of a rectangle is equal to 1 inch less than three times a pe
Marizza181 [45]
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1

This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).

The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.

______
Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.

6 0
3 years ago
1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

g(x) = 4x² + 1

In order to find (g ∘ f)(0) we must first find

(g ° f )(x)

To find (g ° f )(x) substitute f(x) into g(x) that's for every x in g(x) replace it with f(x)

That's

<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

We have

<h3>(g \: \circ \: f)(x) =  {16x}^{2}  + 64x + 17 \\</h3>

Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

We have

<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
3 years ago
If r(x) = 2 – x2 and w(x) = x – 2, what is the range of w(r(x))
Paladinen [302]
Range is the outputs possible
w(r(x))=(2-x^2)-2
w(r(x))=2-x^2-2
w(r(x))=-x^2

therefor the range is from 0 to -∞
5 0
3 years ago
Read 2 more answers
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