h = 50 cos ( pie(x - 10 )/15 ) + 52
80 = 50 cos ( pie( x - 10 )/15 ) + 52
80 - 52 = 50 cos ( pie( x - 10 )/15 )
28 = 50 cos ( pie( x - 10 )/15 )
cos ( pie( x - 10 )/15 ) = 28/50
cos ( pie( x - 10 )/15 ) = 56/100
cos ( pie( x - 10 )/15 ) = cos ( 56 )
cos ( pie( x - 10 )/15 ) = cos ( 0.3111 pie )
Thus ;
pie( x - 10 )/15 = 0.3111 pie
( x - 10 )/15 = 0.3111
x - 10 = 15 × 0.3111
x - 10 = 4.6665
x = 10 + 4.6665
x = 14.6665 [ approximately ]
Thus the correct answer is exactly what u chose goodjob .....
The general form of the geometric sequence is
![a_{n} = a_{1} (r) ^{n-1}](https://tex.z-dn.net/?f=%20a_%7Bn%7D%20%3D%20a_%7B1%7D%20%28r%29%20%5E%7Bn-1%7D%20)
, where a sub n is the number term you're looking for (we're looking for the tenth term). a sub 1 is the first term in the sequence (ours is -6), r is the common ratio, and n-1 is the numbered term you're looking for minus 1. Our formula then looks like this:
![a_{10} =-6(2) ^{10-1}](https://tex.z-dn.net/?f=%20a_%7B10%7D%20%3D-6%282%29%20%5E%7B10-1%7D%20)
. Simplify it to
![a_{10} =-6(2)^9](https://tex.z-dn.net/?f=%20a_%7B10%7D%20%3D-6%282%29%5E9)
. Take 2 to the 9th power then multiply it by -6 to get -3072. C is your answer.
Answer:
x < 1
Step-by-step explanation:
x+9<10
Subtract 9 from each side
x+9-9<10-9
x < 1