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Ivahew [28]
3 years ago
12

If you need 192 beads to make a necklace and bracelet and it takes 5 times more beads to make necklace than bracelet. How many b

eads does it take to make necklace?
Mathematics
1 answer:
Rasek [7]3 years ago
3 0
192 = total beads

necklace + bracelet = 192

Let x equal the number of beads 

bracelet = 5x
necklace = x

5x + x = 192 

6x = 192

x = 32

It takes 32 beads to make a necklace

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kotegsom [21]
Of the line of what?
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3 years ago
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The difference of two trinomials is x2 − 10x + 2. If one of the trinomials is 3x2 − 11x − 4, then which expression could be the
12345 [234]

Answer:

4x^2-21x-2

Step-by-step explanation:

Given that:

Difference of two trinomials is x^2 - 10x + 2

One of the two trinomials is  3x^2 - 11x - 4

To find:

The other trinomial = ?

Four options are:

2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2

Solution:

Let the two trinomials be A and B.

Given A - B = x^2 - 10x + 2

B = 3x^2 - 11x - 4

We have to find the other trinomial A.

A - B = x^2 - 10x + 2

A - (3x^2 - 11x - 4) = x^2 - 10x + 2

\Rightarrow A = x^2 - 10x + 2 + (3x^2 - 11x - 4)

\Rightarrow A = 4x^2-21x-2

So, the correct answer is 4x^2-21x-2.

3 0
3 years ago
Can someone pleas answer this
Dima020 [189]

83.7 m

18.6 / 3.6 = 5.166667

16.2*5.166667 = 83.7 m

7 0
3 years ago
1
Kazeer [188]

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 4, 29) and (x₂, y₂ ) = (0, 28) ← 2 ordered pairs from the table

m = \frac{28-29}{0+4} = - \frac{1}{4}

The line crosses the y- axis at (0, 28 ) ⇒ c = 28

y = - \frac{1}{4} x + 28 ← equation of line → D

8 0
3 years ago
For the problem, use the discriminant to determine the number of real solutions for the equation. Then, find the solutions and c
Ksivusya [100]

Answer:

Discriminant = 55.2 > 0 -> 2 real solutions

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

Step-by-step explanation:

To find the time when the ball will reach the height of 2 meters, we just need to use the value of h = 2 in the equation given. So, we have that:

−4.9t^2 − 4t + 4 = 2

−4.9t^2 − 4t + 2 = 0

For this equation, we have the constants a = -4.9, b = -4 and c = 2. So the discriminant Delta is:

Delta = b^2 - 4ac = 16 + 39.2 = 55.2

sqrt(Delta) = 7.4297

As Delta > 0, we have 2 real solutions

t1 = (-b + sqrt(Delta)) / 2a = (4 + 7.4297) / (-9.8)  = -1.1663 s

t2 = (-b - sqrt(Delta)) / 2a = (4 - 7.4297) / (-9.8)  = 0.35 s

Number of real solutions: 2

Solutions: t1 = -1.1663 s and t2 = 0.35 s

The solution t1 doesn't make sense for this problem, as we can't have a negative value for the time.

So the solution is t2 = 0.35 s

8 0
3 years ago
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