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Natalija [7]
3 years ago
8

Sam feels that students score better on math tests that take place on Fridays. The school provides Sam with the school math test

average, but they cannot separate them by date taken. The school is too large for him to ask every student, so he randomly selects a sample of willing students' test scores after the next Friday's math test. He uses the method of hypothesis testing to compare the Friday scores against the true average of all scores. Frame the correct set of hypotheses for his research. Decide where the rejection region will lie.
Mathematics
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

H0 : μ ≤ x

H1 : μ > x

The hypothesis :

The null hypothesis, H0 : μ ≤ x

The alternative hypothesis, uses the Friday score samples to compare the hypothesis ;

The alternative hypothesis, H1 : μ > 8

For then null, the mean scores is assumed to be the same, and has such mean of Friday's test score takes the value of the population.

Let the population mean value = x

The alternative hypothesis is the claim that the sampled mean gives a greater value than the population mean :

H1 : μ > x

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Read 2 more answers
Afla un numar,stiind ca: a)jumatatea treimii lui este 25; b)sfertul jumatatii lui este 48; c)treimea sfertului sau,marita cu 17
aalyn [17]

Answer:

(a) 150

(b) 384

(c)  84

(d) 261

(e ) 480

Step-by-step explanation:

(a)

Let 'a' be a number such that  the half of his third is 25; i.e.

\dfrac{1}{2}\times(\dfrac{1}{3}a)=25\\\\\dfrca{1}{2\times3}a=25\\\\\dfrac{1}{6}\times a=25\\\\a=25\times6\\\\a=150    

Hence, the number is 150.

(b)

Let 'b' be  the number such that the quarter of his half is 48 i.e.

\dfrac{1}{4}(\dfrac{1}{2}b)=48\\\\\dfrac{1}{8}b=48\\\\b=48\times8\\\\b=384

Hence the number is 384.

(c)

Let 'c' be the number such that the third quarter or, increased by 17 is 80.

\dfrac{3}{4}c+17=80\\\\\dfrac{3}{4}c=80-17\\\\\dfrac{3}{4}c=63\\\\c=\dfrac{63\times4}{3}\\\\c=\dfrac{252}{3}\\\\c=84

Hence, the number is 84.

(d)

Let 'd'  be the number such that its triplet, reduced by 28 is 755

3d-28=755\\\\3d=755+28=783\\\\d=\dfrac{783}{3}\\\\d=261

Hence the number is 261.

(e  

Let 'e' be the number such that double his third, increased by 80 is 400.

\\2\dfrac{1}{3}e+80=400\\\\\dfrac{2}{3}e=400-80=320\\\\e=\dfrac{320\times 3}{2}\\\\e=\dfrac{960}{2}\\\\e=480

Hence, the value of the number is 480.


4 0
4 years ago
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