Step-by-step explanation:
- <em>-x-4=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding x on both sides, we get
- <em>-x-4+</em><em>x=</em><em>4</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>x</em>
- <em>-</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em>
Adding 54 on both sides, we get
- <em>-</em><em>4</em><em>+</em><em>5</em><em>4</em><em>=</em><em>5</em><em>x</em><em>-</em><em>5</em><em>4</em><em>+</em><em>5</em><em>4</em>
- <em>5</em><em>0</em><em>=</em><em>5</em><em>x</em>
Dividing both sides by 5, we get
- <em>5</em><em>0</em><em>/</em><em>5</em><em>=</em><em>5</em><em>x</em><em>/</em><em>5</em>
- <em>1</em><em>0</em><em>=</em><em>x</em>
<em>Hence,</em><em> </em><em>the </em><em>value</em><em> of</em><em> x</em><em> </em><em>is</em><em> </em><em>1</em><em>0</em><em>.</em>
"<span>A company will need 40,000 in 6 years for a new addition. To meet the goal, the company deposits money into an account today that pays 4% annual intrest compund quarterly." Let's pretend that the instructions state, "Determine the amount of money that must be deposited upfront so that you will have $40,000 in 6 years."
Use the Compound Amount formula: A = P(1 + r/n)^(nt),
where P is the principal (the amount deposited upfront), r is the interest rate as a decimal fraction, n is the number of compounding periods, and t is the time in years.
Here, $40000 = P(1 + 0.04/4)^(4*6)
$40000
So the upfront $ needed is P = -------------------------
(1+0.01)^24
This comes out to $31502.65 (answer)</span>
I just did the first one but I don't know is it correct
Alright. What kind of paragraph do you need?
