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vaieri [72.5K]
3 years ago
5

For the school play, tickets cost $9.50 for adults and $3 for kids under 12. What would be the total cost for 8 adult tickets an

d 21 kids tickets? What would be the total cost for aa adult tickets and kk kids tickets?
Mathematics
1 answer:
saul85 [17]3 years ago
4 0

Answer:

  • $139
  • 9.5aa +3kk

Step-by-step explanation:

<h3>a)</h3>

8 adult tickets cost 8($9.50) = $76

21 kids tickets cost 21($3) = $63

The total cost of these tickets is $76 +63 = $139.

__

<h3>b)</h3>

aa adult tickets cost 9.50aa

kk kids tickets cost 3.00kk

The total cost of these tickets is 9.50aa +3.00kk.

_____

<em>Additional comment</em>

We ordinarily expect a variable to be a single letter. This problem statement defines each variable using a double letter, so that is what we have used. (Sometimes Brainly doubles up variable content in copied text, so we suspect that may have happened here.)

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Prove that:
devlian [24]

Answer:

<u>Identities used:</u>

  • <em>1/cosθ = secθ</em>
  • <em>1/sinθ = cosecθ</em>
  • <em>sinθ/cosθ = tanθ</em>
  • <em>cosθ/sinθ = cotθ</em>
  • <em>sin²θ + cos²θ = 1</em>
<h3>Question 1 </h3>
  • (1 - sinθ)/(1 + sinθ) =        
  • (1 - sinθ)(1 - sinθ) / (1 - sinθ)(1 + sinθ) =
  • (1 - sinθ)² / (1 - sin²θ) =
  • (1 - sinθ)² / cos²θ

<u>Square root of it is:</u>

  • (1 - sinθ)/ cosθ =
  • 1/cosθ - sinθ / cosθ =
  • secθ - tanθ
<h3>Question 2 </h3>

<u>The first part without root:</u>

  • (1 + cosθ) / (1 - cosθ) =
  • (1 + cosθ)(1 + cosθ) / (1 - cosθ)(1 + cosθ)
  • (1 + cosθ)² / (1 - cos²θ) =
  • (1 + cosθ)² / sin²θ

<u>Its square root is:</u>

  • (1 + cosθ) / sinθ =
  • 1/sinθ + cosθ/sinθ =
  • cosecθ + cotθ

<u>The second part without root:</u>

  • (1 - cosθ) / (1 + cosθ) =
  • (1 - cosθ)²/ (1 + cosθ)(1 - cosθ) =
  • (1 - cosθ)²/ (1 - cos²θ) =
  • (1 - cosθ)²/sin²θ

<u>Its square root is:</u>

  • (1 - cosθ) / sinθ =
  • 1/sinθ - cosθ / sinθ =
  • cosecθ - cotθ

<u>Sum of the results:</u>

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4 0
3 years ago
Read 2 more answers
One of the legs of a right triangle measures 8 cm and its hypotenuse measures 14 cm.
Ugo [173]

Answer:

about 11.5 cm.

Step-by-step explanation:

I know the measurement of the other leg is about 11.5 cm. I know because I used the Pythagorean theorem.

a^2+b^2=c^2.

"a" and "b" are the values of the legs of the triangle, while "c" is the measure of the hypotenuse. We know that 8cm is the measure of one of the legs, and 14 cm is a measure of the hypotenuse.

8^2+b^2=14^2 simplified: 64+b^2=196

Then, I subtracted 64 on both sides, so I would have "b" by itself.

b^2=132

Next, I found the square root of both b^2 and 132, so I would find the true value of "b."

b=11.4891252931

So, the measure of the other leg rounded to the nearest tenth is about 11.5.

3 0
3 years ago
I need the answer fast please
iogann1982 [59]

Answer:

A'

Step-by-step explanation:

It is A' because they are corresponding angles, it is the same exact shape it has just been translated to a different area of the graphic plane.

If my answer is incorrect, please notify me and I'll assess what it was that I did wrong.

3 0
3 years ago
YOOOO WHO WANNA VAPE WITH ME ????
Tom [10]

Answer:

but  you have to help me

Step-by-step explanation:

5 0
3 years ago
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Historical data for a local manufacturing company show that the average number of defects per product produced is 2. In addition
charle [14.2K]

Answer:

The probability that there will be a total of 7 defects on four units  is 0.14.

Step-by-step explanation:

A Poisson distribution describes the probability distribution of number of success in a specified time interval.

The probability distribution function for a Poisson distribution is:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}, x=0,1,2,3,...

Let <em>X</em> = number of defects in a unit produced.

It is provided that there are, on average, 2 defects per unit produced.

Then in 4 units the number of defects is, (2\times4)=8.

Compute the probability of exactly 7 defects in 4 units as follows:

P(X = x)=\frac{e^{-\lambda}\lambda^{x}}{x!}\\P(X=7)=\frac{e^{-8}8^{7}}{7!}\\=\frac{0.0003355\times2097152}{5040}\\ =0.1396\\\approx0.14

Thus, the probability of exactly 7 defects in 4 units is 0.14.

8 0
3 years ago
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