Please help me i cant figure it out.

The arena wants to estimate the previous two month’s ticket-sale income. in total, 71,115 people attended different events at th

OleMash [197]

There was a total of 71,115 people who attended the different events in the arena for the past two months,

The estimated average ticket price is $ 21.15.

We need to solve for the estimated arena's ticket sale income and the solution is shown below:
Ticket Sale Income = 71, 115 * $21.15
Ticket Sale Income = $1,504,082

3 0

4 years ago

It takes me 12 minutes to run 2 kilometers. How long will it take me to run 10,000 meters?

galina1969 [7]

60min or 1 hour

Because 2km is equal to 2000m
Therefore you multiply 12 min by 5 (because 2000m x 5 is 10000m)

7 0

3 years ago

Algebraic of coefficient of 3

N76 [4]

In an algebraic expression, terms are the elements separated by the plus or minus signs. This example has four terms, 3x2, 2y, 7xy, and 5. Terms may consist of variables and coefficients, or constants.

Variables
In algebraic expressions, letters represent variables. These letters are actually numbers in disguise. In this expression, the variables are x and y. We call these letters "variables" because the numbers they represent can vary—that is, we can substitute one or more numbers for the letters in the expression.

Coefficients
Coefficients are the number part of the terms with variables. In 3x2 + 2y + 7xy + 5, the coefficient of the first term is 3. The coefficient of the second term is 2, and the coefficient of the third term is 7.

If a term consists of only variables, its coefficient is 1.

Constants
Constants are the terms in the algebraic expression that contain only numbers. That is, they're the terms without variables. We call them constants because their value never changes, since there are no variables in the term that can change its value. In the expression 7x2 + 3xy + 8 the constant term is "8."

Real Numbers
In algebra, we work with the set of real numbers, which we can model using a number line.

5 0

4 years ago

Don't know need help [pls

NeX [460]

Answer:

56

......................................................

8 0

3 years ago

Integrated circuits consist of electric channels that are etched onto silicon wafers. A certain proportion of circuits are defec

boyakko [2]

Answer:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=33 represent the number of circuits that show evidence of undercutting

$\hat p=\frac{33}{1000}=0.033$ estimated proportion of circuits that show evidence of undercutting

$p_o=0.05$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that they reduce the rate of undercutting to less than 5%.:

Null hypothesis: $p\geq 0.05$

Alternative hypothesis: $p < 0.05$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

4 0

3 years ago