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2 years ago

4y (4y - 4) - 4 (-4 + 5 + 4y²) please simplify <3

Mathematics

1 answer:

sasho [114]2 years ago

5 0

Answer:

16y - 4

Step-by-step explanation:

4y(4y - 4) - 4(- 4 + 5 + 4y^2)

16y - 16y - 4(1 + 4y^2)

16y - 16y - 4(4y^2 + 1)

16y^2 - 16y^2 + 4

16y - 4

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aev [14]

Answer:

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Step-by-step explanation:

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2 years ago

Area of a rectangular field is 2c^3-c^2+6 square units. If the length of the field is c-2 units, what is its width ?

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2 years ago

An airplane flies at 250 mph. How far will it travel in 5 hours at that rate of speed?

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3 years ago

Read 2 more answers

Solving Square Roots Worksheet (x - k)^2 : Part 1

iVinArrow [24]

Answer:

1. x = +/- 2 $\sqrt{2}$ - 7

2. x = $3$ +/- $2i\sqrt{3}$

3. n = $2$ +/- $i\sqrt{2}$

Step-by-step explanation:

1. Divide both sides by 2: (x + 7)^2 = 8

Square root both sides: x + 7 = +/- 2 $\sqrt{2}$

Subtract 7 from both sides: x = +/- 2 $\sqrt{2}$ - 7

2. Square root both sides: x - 3 = $\sqrt{-12}$

Since there is a negative inside the radical, we need to have an imaginary number: $i=\sqrt{-1}$ . So, $\sqrt{-12} =i\sqrt{12} =2i\sqrt{3}$

Add 3 to both sides: x = $3$ +/- $2i\sqrt{3}$

3. Divide by -5 from both sides: (n - 2)^2 = -2

Square root both sides: n - 2 = $\sqrt{-2}$

Again, we have to use i: $n-2=\sqrt{-2} =i\sqrt{2}$

Add 2 to both sides: n = $2$ +/- $i\sqrt{2}$

Hope this helps!

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2 years ago

Read 2 more answers

Solve the system of equations by graphing.

k0ka [10]

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