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Strike441 [17]
2 years ago
12

5._35 rounded to the nearest whole number is 5? Giving brainlists

Mathematics
2 answers:
Tatiana [17]2 years ago
4 0

Answer:

yes it is 5

Step-by-step explanation:

densk [106]2 years ago
3 0

Answer:

5.035 rounded the the nearest whole number is 5.

You might be interested in
0.611111111. .. repeating equals<br> Q. 12/19<br> b. 11/18<br> c. 13/20<br> d. 10/17
-Dominant- [34]

Answer:

B. 11/18

Step-by-step explanation:

Solve using algebra.

x = 0.611111...

10x = 6.111111...

10x - x = 6.111111.. - 0.61111111..

9x = 5.5

x = 5.5/9

x = 11/18

7 0
3 years ago
Find the value of the trigonometric ratio. Make sure to simplify the fraction if needed. plss help
Natalija [7]

Answer:

3/5

Step-by-step explanation:

sinA = opp/hyp

= 21/35

= 3/5

8 0
3 years ago
Solve for t.
wlad13 [49]

One solution was found :  t ≤ -13 (number 4)

Pull out like factors :

-3t - 39  =   -3 • (t + 13)

Divide both sides by  -3  

Remember to flip the inequality sign:  

Solve Basic Inequality :

Subtract  13  from both sides to get t≤−13

7 0
3 years ago
Which of the following is something that should not be a consideration when choosing a health care plan?
saw5 [17]
The HOC FM tv U.N. jus us fox
6 0
3 years ago
Read 2 more answers
There are 9 performers who are to present their acts at a variety show. How many different ways are there to schedule their appe
nika2105 [10]
For this type of question it is easiest to think about it in terms of a simple multiplication. The way we can do this is by working out how many possibilities there are for each position on the program. This is as follows:
For the first act, there are 9 possible performers we can pick
For the second act, because we have already assigned a performer to the first act, there are only 8 possible performers
For the third act, because we have already assigned a performer to the first two acts, there are only 7 possible performers
This goes on and on until we reach the final act, where we have used all the performers except one.
Therefore we can say:
For the first act there are 9 possibilities
For the second act there are 8 possibilities
For the third act there are 7 possibilities
For the fourth act there are 6 possibilities and so on
If we want to write this mathematically we can just say that there are:
9 possibilities x 8 possibilites x 7 possibilities etc right down until we are at the final act where there is 1 possibility.
To write this out as an equation we just say:
9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = the number of different ways
In maths however, we have a much simpler way of saying this, which we call "factorial".
That whole stream of numbers up there can just be said to be "9 factorial", or if we are writing it in an equation "9!". You may find that your calculator has a button which has an "!" on it. If you put in the number of performers and then press the "!" button, it will give you the answer to your question.
Hope this helped you :)
3 0
3 years ago
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