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2 years ago

Problem

Mathematics

2 answers:

mars1129 [50]2 years ago

8 0

It’s probably A or C

Studentka2010 [4]2 years ago

3 0

The answer is A and C

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30 POINTS! Use set builder notation to represent the following set. {... -3, -2, -1, 0}

Wittaler [7]

{x | x I, x ≤ 0}
because I is the Integers

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3 years ago

I need to know what the equation is for this graph..

Lostsunrise [7]

Answer:

The choice second

$y = \frac{1}{3} \times ( \frac{1}{4} ) ^{x}$

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2 years ago

-4y+4=10x standard form ik its 10x+4y=4 but you need to simplify more please help i need to get it in an hr

LuckyWell [14K]

Answer:

x= (2/5)-(2y/5) (Im not sure if this is what you need but this is the answer simplified)

Step-by-step explanation:

Move all terms that don't contain x to the right side and solve.

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2 years ago

Prove : sin²θ + cos²θ = 1 thankyou ~

Gnom [1K]

Answer:

See below

Step-by-step explanation:

Here we need to prove that ,

$\sf\longrightarrow sin^2\theta + cos^2\theta = 1$

Imagine a right angled triangle with one of its acute angle as $\theta$ .

The side opposite to this angle will be perpendicular .
Also we know that ,

$\sf\longrightarrow sin\theta =\dfrac{p}{h} \\$

$\sf\longrightarrow cos\theta =\dfrac{b}{h}$

And by Pythagoras theorem ,

$\sf\longrightarrow h^2 = p^2+b^2 \dots (i)$

Where the symbols have their usual meaning.

Now , taking LHS ,

$\sf\longrightarrow sin^2\theta +cos^2\theta$

Substituting the respective values,

$\sf\longrightarrow \bigg(\dfrac{p}{h}\bigg)^2+\bigg(\dfrac{b}{h}\bigg)^2\\$

$\sf\longrightarrow \dfrac{p^2}{h^2}+\dfrac{b^2}{h^2}\\$

$\sf\longrightarrow \dfrac{p^2+b^2}{h^2}$

From equation (i) ,

$\sf\longrightarrow\cancel{ \dfrac{h^2}{h^2}}\\$

$\sf\longrightarrow \bf 1 = RHS$

Since LHS = RHS ,

Hence Proved !

I hope this helps.

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2 years ago

Margie pays $9.43, which includes 15%

andrew-mc [135]

Answer:

15% $1.41 $10.84

10.84

8 0

3 years ago