Answer:
Problem
2 answers:
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Answer:
The half-life of the radioactive substance is 135.9 hours.
Step-by-step explanation:
The rate of decay is proportional to the amount of the substance present at time t
This means that the amount of the substance can be modeled by the following differential equation:
Which has the following solution:
In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.
After 6 hours the mass had decreased by 3%.
This means that . We use this to find r.
So
Determine the half-life of the radioactive substance.
This is t for which Q(t) = 0.5Q(0). So
The half-life of the radioactive substance is 135.9 hours.
Answer:
-7, 15
Step-by-step explanation:
The positive difference between E and G is 11.
<h3>Solution</h3>G - E = 11
G = 11 + E = 11 + 4
G = 15 . . . . . . . . . . . . . when G is right of E
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E - G = 11
E - 11 = G = 4 - 11
G = -7 . . . . . . . . . . . . when G is left of E
Possible coordinates for G are -7 and 15.
