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3 years ago

Can yall pls help !!!

Mathematics

1 answer:

motikmotik3 years ago

5 0

Answer:

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░░░▌░▄▄▄▐▌▀▀▀░░ This is Bob

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▀█▌░░░▄░▀█▀░▀ ░░ Copy And Paste Him onto all of ur brainly answers

░░░░░░░▄▄▐▌▄▄░░░ So, He Can Take

░░░░░░░▀███▀█░▄░░ Over brainly

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do it or he will hunt you down and kill u (lets destroy the moderators!!!!!!!!)

we are slowing them down already! good work soilders!

Step-by-step explanation:

Step-by-step explanation:

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PLEASE ANSWER ASAP!!! I HAVE 2 HRS!!!

garik1379 [7]

Answer:

Step-by-step explanation:

6 0

2 years ago

Find the diameter of a circle if the radius is equal to 8?

Andru [333]

The diameter is 16 so that is the answer<span />

8 0

3 years ago

A pyramid has a base area of 44cm and a height of 12.6 cm what is the volume of the pyramid ?

aliya0001 [1]

Answer:

184.8 cubic cm

Step-by-step explanation:

The formula for the volume of a pyramid is

V = (1/3)(B)(h) where B is the area of the base, and h is the height

We are given B = 44 cm² andh = 12.6cm

Plug them into the formula and simplify...(I'm assuming you are allowed to use a calculator for these problems)

V = (1/3)(44cm²)(12.6cm)

<h2> V = 184.8 cm³ or 184.8 cubic cm</h2><h2 />

7 0

3 years ago

The United States has about 34,000,000 telephones. The rest of the world has about 23,000,000 telephones.

NikAS [45]

Answer:

57,000,000

Step-by-step explanation:

1. Sum the numbers 34,000,000 + 23,000,000= 57,000,000

4 0

3 years ago

Read 2 more answers

The edge of a cube was found to be 30 cm with a possible error in measurement of 0.5 cm. Use differentials to estimate the maxim

erica [24]

Answer with Step-by-step explanation:

We are given that

Side of cube, x=30 cm

Error in measurement of edge, $\delta x=0.5$ cm

(a)

Volume of cube, $V=x^3$

Using differential

$dV=3x^2dx$

Substitute the values

$dV=3(30)^2(0.5)$

$dV=1350 cm^3$

Hence, the maximum possible error in computing the volume of the cube

= $1350 cm^3$

Volume of cube, $V=(30)^3=27000 cm^3$

Relative error= $\frac{dV}{V}=\frac{1350}{2700}$

Relative error=0.05

Percentage error= $0.05\times 100=5$ %

Hence, relative error in computing the volume of the cube=0.05 and

percentage error in computing the volume of the cube=5%

(b)

Surface area of cube, $A=6x^2$

$dA=12xdx$

$dA=12(30)(0.5)$

$dA=180cm^2$

The maximum possible error in computing the volume of the cube= $180cm^2$

$A=6(30)^2=5400cm^2$

Relative error= $\frac{dA}{A}=\frac{180}{5400}$

Relative error in computing the volume of the cube=0.033

The percentage error in computing the volume of the cube= $0.033\times 100=3.3$ %

4 0

2 years ago