After rearranging the formula to get a on one side you get:
a = (V-T)/b
Ok let’s solve it
5(x-2)^2-20=0
first let’s foil (x-2)
5(x^2-4x+4) -20=0
now distribute the 5
5x^2 -20x +20 -20 = 0
combine like terms
5x^2-20x=0
take the gcf
5x(x-4)=0
x=0, 4
solutions are (4,0) and (2, -20) because the original vertex form a(x-h)^2+k
Image of question is not attached
Answer:
f(4)= 15
Step-by-step explanation:
f (x) =6x-9
= 6(4)-9
=24-9
f(4) = 15